The equation of the line that is tangent to the circle at (8, -2) is:
We know that the line which is tangent at a point on a circle is perpendicular to the line joining the center of the circle and that point.
Here we are given the equation of a circle as:
The center of the circle is at: (3,-2)
( Since, the standard form of a circle with center at (h,k) and radius r is given by:
)
Also, the equation of a line joining (3.-2) and (8,-2) is given by:
Also, we know that the slope of this line is zero.
Also, we know that if two lines are perpendicular with slope m and m' respectively then,
Hence, we get that the slope of the tangent line is:
Also, we know that:
The equation of a line with given slope m' and a passing through point (a,b) is given by:
Here (a,b)=(8,-2)
and
i.e. the equation of the tangent line is:
With working out
17x - 6 + 3x - 5 = x + 11 + 4x
Answer:the domain of the parent function f(x) = |x| is all real numbers, and the range is all non-negative real numbers.
Step-by-step explanation:
(This answer was AI generated)