what is the exact value of sin 22.5 degrees using the sum, difference, half, or double angle formulas and the exact value chart in the solution.

Answers

Answer 1

Answer: $cos 2x=1-2sin^2x \n cos 45^0=1-2sin^2(22,5)^0 \n ( √(2) )/(2) =1-2sin^2(22,5)^0 \to sin(22,5)^0= \frac{ \sqrt{2- √(2) } }{2}$

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26 students in a hostel have provisions for 60 days if 10 more student are admitted to the hostel for how many days would the provisions be enough?

Answers

Answer:

About 43 days

Step-by-step explanation:

Let's assume that the provisions in the hostel are consumed at a constant rate by each student per day. To find out how long the provisions would last with an additional 10 students, we need to consider the total number of students after the new admissions.

Initially, there are 26 students, and the provisions last for 60 days. Therefore, the total provision "student-days" is 26 students multiplied by 60 days, which equals 1560 student-days.

If 10 more students are admitted, the total number of students becomes 26 + 10 = 36 students.

To calculate how many days the provisions would last for 36 students, we divide the total provision "student-days" by the new total number of students:

1560 student-days / 36 students = 43.33 days (approximately)

Therefore, with 10 more students admitted, the provisions would be enough for approximately 43 days.

Answer:

44 days for the 36 students.

Step-by-step explanation:

Let's break down the information given:

Initially, there are 26 students in the hostel and provisions for 60 days. This means that the total "student-days" that the provisions can support is 26 students * 60 days = 1560 student-days.

Now, 10 more students are admitted to the hostel. So, the total number of students becomes 26 + 10 = 36 students.

We want to find out for how many days the provisions will be enough for these 36 students.

We can set up a proportion to solve this:

Initial student-days = New student-days

1560 student-days = 36 students * x days

Now solve for x:

x = 1560 student-days / 36 students

x = 43.33 days

Since you can't have a fraction of a day, we'll round up to the nearest whole day. Therefore, the provisions would be enough for approximately 44 days for the 36 students.

HELP ASAP Solve log7 b > 2. Question 18 options: b > 7 b > 49 b > 2–7 b > 14

Answers

Answer: Second Option

$b > 49$

Step-by-step explanation:

We have the following expression:

$log_7(b) > 2$

We have the following expression:

To solve the expression, apply the inverse of $log_7$ on both sides of the equality.

Remember that: $b ^ {log_b (x)} = x$

So we have to:

$7^(log_7(b)) > 7^2$

$b > 7^2$

$b > 49$

The answer is the second option

WHAT IS THE NEXT VALUE 4D7G10J13

Answers

Answer:

The next letter is M and the next number is 16.

Step-by-step explanation:

Given: 4D7G10J13

It follows a pattern.

D is the 4th alphabet

G is the 7th alphabet

J is the 10th alphabet

Now we have to find 13th alphabet, which is M.

M is the 13th alphabet.

Therefore, the next letter is M and the next number is 16.

The next letter is M and the next number is 16.

The given code is 4D7G10J13

Here, the number pattern is

4+3=7

7+3=10

10+3=13

13+3=16

So, the next number is 16.

The letter pattern is

D is the 4th alphabet

G is the 7th alphabet

J is the 10th alphabet

Now we have to find 13th alphabet, which is M.

M is the 13th alphabet.

Therefore, the next letter is M and the next number is 16.

Learn more about the pattern here:

brainly.com/question/23136125.

#SPJ6

Help!! Can someone put me out my misery

Answers

Answer: 0.14

Step-by-step explanation:

1) Find the total #of seniors. To do this add up 25+5+5 = 35.

2)Since we know the number of seniors that work just do 5/35. This simplifies to 0.14 rounded to the nearest hundreth.

How do you solve x+2/3=11//12

Answers

$x+(2)/(3)=(11)/(12)\ \ \ /-(2)/(3)\n\nx=(11)/(12)-(2)/(3)\n\nx=(11)/(12)-(2\cdot4)/(3\cdot4)\n\nx=(11)/(12)-(8)/(12)\n\nx=(11-8)/(12)\n\nx=(3)/(12)\n\n\underline{\underline{x=(1)/(4)}}$