An electric dryer consumes 6.0 × 10^6 joules ofelectrical energy when operating at 220 volts for
1.8 × 103 seconds. During operation, the dryer
draws a current of
(1) 10. A (3) 9.0 × 102 A
(2) 15 A (4) 3.3 × 103 A

Answers

Answer 1
Answer:

Answer : The dryer draws a current of 15 A.

Explanation :

Given that,

Energy consumed, E=6* 10^6\ J

Voltage, V = 220 Volts

Time, t=1.8* 10^3\ s

Power dissipated is given by :

P=(E)/(t)

Also, P = VI

So, VI=(E)/(t)

I=(E)/(Vt)

I=(6* 10^6\ J)/(220\ V* 1.8* 10^3\ s)    

I=15\ A

So, the correct option is (2)

Hence, this is the required solution.                                                  

Answer 2
Answer:

The dryer draws a current of 15 A.Electric currents is the ratio of charge per unit of time.

What is electric current?

The pace at which electrons travel through a conductor is known as electric current. The ampere is the SI unit for electric current.

Electrons are tiny particles that reside within a substance's molecular structure.

The given data in the problem is;

V is the voltage= 220 volts

E is the electric energy= 6.0 × 10⁶

t is the time =1.8 × 10³ seconds.

I is the electric current=?

The electric current is found as;

\rm P= (E)/(t) \n\n\ P= VI \n\n VI = (E)/(t) \n\n I= (E)/(VT) \n\n I= (6 * 101^6 )/(220 * 1.8 * 10^3) \n\n \rm I= 15 A

Hence the dryer draws a current of 15 A.Electric currents is the ratio of charge per unit of time.

To learn more about the electric current refer to the link;

brainly.com/question/7643273


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Answers

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Answers

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Answers

Answer:

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Explanation:

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Answers

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Answers

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Answers

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Explanation: