High temperatures increase the activation energy of the reaction.
High temperatures make the gas molecules move more quickly.
The reaction becomes exothermic at high temperatures.
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the correct answer is C i got 100% on it
Ca3(PO4)2
There will be two atoms of phosphorus in the 1.75 mol of calcium phosphate.
Atoms are the smallest unit of matter. In a chemical reaction, the number of atoms shows the quantity of an element in the compound or reaction. Phosphorus is a chemical element that is preset in the periodic table.
In calcium phosphate, Ca3(PO4)2, the number of atoms can be calculated by counting the number of moles that is given in the equation.
The number of atoms of calcium is 3, and the number of phosphorus atoms is 2.
Now given the 1.75 mol of calcium phosphate, so the number of atoms of phosphorus will be the same in any number of moles of calcium phosphate. So there will be 2 atoms of phosphorus in the given equation.
Thus, the number of atoms is two.
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Answer:
It has 2 phosphorus atoms in 1 mol
so for 1.75 mol =2×1.75
Explanation:
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Answer : Yes, the concentrated is a catalyst in this reaction.
Explanation :
Catalyst : It is a substance that increase the rate of chemical reaction but it is not consumed by the reaction. That means catalyst can be recovered chemically at the end of the reaction.
The given balanced chemical reaction is,
From the balanced chemical reaction we conclude that the amount of present in the reactant side are remains same as the amount of present in the product side. That means the amount of is not consumed by the reaction and it can be recovered chemically at the end of the reaction.
Hence, yes, concentrated is a catalyst in this reaction.
Answer:
Explanation:
a that the ansawer
Using Gay-Lussac's Law, we calculate that when the temperature of a gas increases from 320 K to 450 K, the pressure of the gas will increase from 1.5 atm to 2.1 atm, assuming the volume and the amount of gas remain constant.
To answer the question, we need to use the concept in physics called Gay-Lussac's Law. This law states that the pressure of a given amount of gas held at a constant volume is directly proportional to the Kelvin temperature. It's also important to remember that when we're dealing with gases, temperatures have to be in Kelvin for our calculations to work.
Given that, we know that the initial pressure (P1) is 1.5 atm, the initial temperature (T1) is 320K, and the final temperature (T2) is 450K. We want to find the final pressure (P2). According to Gay-Lussac's law, this can be calculated using the following equation: P1/T1 = P2/T2.
Thus, P2 = P1 * T2 / T1 = 1.5 atm * 450K / 320K = 2.1 atm.
So, the gas pressure will be 2.1 atm when the temperature increases from 320 K to 450 K, assuming that the volume and the amount of gas remain constant.
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