Answer: (1) H+ ions in aqueous solution
Answer:
2.7*10^23
Explanation:
first work out the moles
So do 36g / 80 (80 is bromine's relative Atomic Mass number)
You have 0.45 M
Then, do 0.45 * 6.02*10^23
You get 2.7*10^23, which is your answer
Answer:
11.0L of carbon dioxide is produced
Explanation:
Balanced equation:
According to balanced equation, 1 mol of produces 1 mol of
So, 0.489 mol of produces 0.489 mol of
Let's assume behaves ideally.
So,
where P is pressure, V is volume , n is number of moles, R is gas constant and T is temperature in kelvin
Plug-in all the values in the above equation-
or,
So, 11.0L of carbon dioxide is produced
High stability over long time and source need not be replaced
High penetration and high ionization
A good source of beta radiation and has a half-life of 432 years
Answer:
Ionization smoke detectors use americium as a source of alpha particles. Alpha particles from the americium source ionize air molecules. This makes some particles positively charged and some negatively charged. ... Because of this shielding, the smoke detector poses no radiation health risk when they are properly handled.
Explanation:
Hope this helped! :D
Answer:
Second graph is more reactive.
Explanation:
I just did the lesson myself, chose the first graph, and obviously got it wrong.
Therefore I can tell you with 100% certainty that the correct answer is graph #2 in this case. Hope this helps.
C₂H8 is Dimethocain-M. In C₂H₈ two atoms of carbon are present. Combustion of 6.40 mole C₂H₈ produced 12.8 moles of CO₂.
Combustion reaction refers to burning of compound in presence of oxygen. The reaction is accompanied by heat and light. One mole of burned carbon produced one mole of CO₂ gas.
Combustion is a chemical reaction between substances ,usually including oxygen and usually accomplished by the generation of heat and light.
Here we see that in C₂H₈ there are there are two carbons present then 2 moles of CO₂ gas is produced i.e. 2 × 6.40 = 12.8 moles.
Hence, 12.8 moles of CO₂ produced in combustion of 6.40 mole C₂H₈.
To learn more about combustion refer the link below;
#SPJ2
A. The reaction will stop.
B. The reaction will slow down.
C. The reaction will speed up.