Which of the following intervals represents the set (1,4) u [2,6]?a. (1,6]
b. (4,6]
c. [2,4)
d. (2,6]

Please show work,

Thanks!

Answers

Answer 1
Answer: (1;\ 4)\ \cup\ [2;\ 6]=(1;\ 6]\n\nAnswer:A.
Answer 2
Answer: Set is a sum of two intervals :(1,4) u [2,6] 
In the first interval it is open on both sides so 1 and 4 don't belong to this interval, the second is closed so both 2 and 6 belong to interval and numbers between 2 and 6
We can write it as 1<x\leq 6
summing both sets we have one set: (1,6]
so
a) represent our set
b) also represent because all numbers between 4-6 and 6 are in our set
c)also represent, all numbers are in main set
d)also represent


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Alan can chop 3/4 of a carrot in 1/8 min.How many carrots can he chop in 1 min?

(I want to see how fast Brainly is)

Answers


(3/4 carrot) / (1/8 minute) = ('x' carrots) / (1 minute)

Cross-multiply the proportion:

   (3 carrot / 4 minutes) = ( 'x' carrot / 8 minutes)

Multiply each side by 8 minutes:

               6 carrots  =  'x' carrots


well 3/4 in 1/8 means that you need to multiply 3/4 by 8 in order to make a whole minute
3/4 × 8/1 = 24/4
24/4=6
the answer is 6 carrots 
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Which of the following represents an equation for the line that is parallel to y=3/2x-7 and qhich passes through the point (6,8)? 1) y-8=-2/3(x+6) 3)y+8=3/2(x-6)
2)y-8=3/2(x+6) 4)y+8=-2/3(x-6)

Answers

answer:  

1)y-8=-2/3(x+6) 3)y+8=3/2(x-6)

Which is bigger 21,480 ml or 214.8 l

Answers

If you would like to know which is bigger, you can calculate this using the following steps:

21,480 ml or 214.8 l

21,480 ml = 21.48 l
21.48 l < 214.8 l

The correct result would be: 214.8 l is bigger than 21,480 ml.
I hope this helps you

The quantity demanded per month, x, of a certain make of personal computer (PC) is related to the average unit price, p (in dollars), of PCs by the equationx = f(p) =1009810,000 − p2It is estimated that t mo from now, the average price of a PC will be given byp(t) =4001 +18t+ 200 (0 ≤ t ≤ 60)dollars. Find the rate at which the quantity demanded per month of the PCs will be changing 16 mo from now. (Round your answer to one decimal place.)

Answers

Answer:

The value of dx/dt is (100p)/(9√((810000-p^2))).(1600)/(√(t)\left(√(t)+8\right)^2)\n while the rate of change of quantity demanded per month after 16 months is 18.7.

Step-by-step explanation:

From the given data the equation of quantity demanded for average price is given as  is given as

x=f(p)=(100)/(9)√(810000-p^2)

The equation of average price p for a given value of t is given as

p(t)=(400)/(1+(1)/(8)√(t))+200

Now in order to determine the rate at which the quantity demanded will be changing is given as (dx)/(dt)

This is found by using the chain rule as

(dx)/(dt)=(dx)/(dp).(dp)/(dt)

Now

(dx)/(dp)=(d((100)/(9)√(810000-p^2)))/(dp)\n(dx)/(dp)=(100)/(9)(d)/(dp)[(810000-p^2)^(1/2)]\n(dx)/(dp)=(100)/(9)(1)/(2)[(810000-p^2)^(-1/2)](d)/(dp)[(810000-p^2)]\n(dx)/(dp)=(50)/(9)[(810000-p^2)^(-1/2)](-2p)\n(dx)/(dp)=(100p)/(9√((810000-p^2)))

Now

\n(dp)/(dt)=(d((400)/(1+(1)/(8)√(t))+200))/(dt)\n(dp)/(dt)=(d)/(dt)\left((400)/(1+(1)/(8)√(t))+200\right)\n(dp)/(dt)=(d)/(dt)\left((400)/(1+(1)/(8)√(t))\right)+0\n(dp)/(dt)=400(d)/(dt)\left((1)/(1+(1)/(8)√(t))\right)\n(dp)/(dt)=400(d)/(du)\left(\left(1+(1)/(8)√(t)\right)^(-1)\right)(d)/(dt)\left(1+(1)/(8)√(t)\right)\n(dp)/(dt)=-(1600)/(√(t)\left(√(t)+8\right)^2)

So now the value of dx/dt is given as

(dx)/(dt)=(dx)/(dp).(dp)/(dt)\n(dx)/(dt)=(100p)/(9√((810000-p^2))).(1600)/(√(t)\left(√(t)+8\right)^2)\n

So the value of dx/dt is (100p)/(9√((810000-p^2))).(1600)/(√(t)\left(√(t)+8\right)^2)\n

Now for the time =16 months price is given as

p(t)=(400)/(1+(1)/(8)√(t))+200\np(16)=(400)/(1+(1)/(8)√(16))+200\np(16)=466.67

Now the value of x is given as

(dx)/(dt)=(100p)/(9√((810000-p^2))).(1600)/(√(t)\left(√(t)+8\right)^2)\n\n(dx)/(dt)=(100*466.67)/(9√((810000-466.67^2))).(1600)/(√(16)\left(√(16)+8\right)^2)\n(dx)/(dt)=18.72

So the rate of change of quantity demanded per month after 16 months is 18.72

Is 2.99 greater than 3.51

Answers

Yes 2.99 is greater than 3.15 because The 3 is greater than 2 so you can see that its greater than:)
hope that helped :)
Yes because if you look at the ones place, 2 and 3, you see that 3 is greater than 2 so there fore it is false.

In the parking lot at Central, there are 21 blue cars and 75 cars total. What is the ratio of blue cars to cars that are not blue in simplest form?

Answers

Answer: The ratio of blue cars to cars that are not blue in simplest form = 7:18

Step-by-step explanation:

Given: There are 21 blue cars and 75 cars total.

Then, number of cars that are not blue = 75 -21 = 54

Now, the ratio of blue cars to cars that are not blue = (21)/(54)=(7)/(18) [Divide numerator and denominator by 3.]

Hence, the ratio of blue cars to cars that are not blue in simplest form = 7:18