How does the absorption and release of energy affect temperature change during a chemical reaction?

Answers

Answer 1

Answer: It depends. If you are talking about the temperature of the chemicals in the reaction, than the temperature increases due to increasing enthalpy. However, if you are talking about the temperature of the surrounding, than the temperature of the surrounding would actually decrease since heat is being taken away from the environment into the reaction.

Answer 2

Answer: if heat is absorbed, the temperature increases but if heat is released, the temperature decreases :))
i hope this be helpful
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Describe a procedure to separate a mixture of sugar, black pepper, and pebbles.

Answers

Answer : The procedure to separate the mixture of sugar, black pepper and pebbles would require physical methods.

First step is to pass the mixture through a grid that traps the pebbles in it and allows the passage of black pepper and sugar from it or alternatively, physically hand-picking up the pebbles can also be done.

Next step is to add water to the mixture to the sugar and black pepper, stir this solution until all the sugar dissolves in the water. Then pass this solution from a filter paper and collect the filtrate in a beaker.

The residue would contain the black pepper on it, it can be dried after separation.

To obtain the sugar which is dissolved in water, one can evaporate the water in it and get the sugar at the bottom of the beaker.

Pass the mixture through a screen to allow the salt and pepper to pass through but traps the pebbles. Mix the salt and pepper with water to dissolve the salt and filter it to get the pepper.

What happens to the molecules in a gas when it condenses?

Answers

when gas molecules condence they become a liquid and if the liquid molecules condence they turn into a solid but the solid molecules cannot condence

How much protons and electrons does aluminum have

Answers

13 for both electrons and protons

Assume that each tablet's mass was 1,000 mg, and remember that you used 0.200 L of water each time. Compute the reaction rate to the nearest whole number using the formula below.

Answers

Answer:

For every temperature you use the formula given by the question.

at 3°C you have:

Reaction rate = (1000/0.2)/138.5 = 36 mg/L/sec

at 24°C you have:

Reaction rate = (1000/0.2)/34.2 = 146 mg/L/sec

at 40°C you have:

Reaction rate = (1000/0.2)/26.3 = 190 mg/L/sec

at 65°C you have:

Reaction rate = (1000/0.2)/14.2 = 352 mg/L/sec

Explanation:

Answer:

see below

Explanation:

3°C: 36

24°C: 146

40°C: 190

65°C: 352

Full table: 145

Eight pieces: 173

Tiny pieces: 216

13. _____ The mass of 3.75 mol of KF(s) isa. 3.75 g
b. 58.1 g
c. 217.8 g
d. 108.9 g

Answers

Answer:

C. 217.8 g

Explanation:

First, we find the weight of KF. notice they are 1:1 ratio. so the molar mass of K is 39.0983 and Fluorine is 18.998403

we add them together we get 58.09 g/mol

now to find the mass we do

$(58.096 Grams)/(mol)$ * 3.175 mol

mol and mol cancel out, we left with 58.096 grams * 3.75

if you multiply you get 217.86 grams.

PLZ HELP AND ILL GIVE YOU BRAINLIEST!!!Match each molecular formula to the corresponding empirical formula.

1) C4H8O2
2) C4H12O4
3) C2H10O2

A) CH3O
B) CH5O
C) C2H4O

Answers

Answer:

1) C4H8O2 = C2H4O

2) C4H12O4 = CH3O

3) C2H10O2 = CH5O

Explanation:

The empirical formula is the formula that indicates the relative proportions of the elements in a molecule rather than the actual number of atoms of the elements. It tells us the simplest ratio of elements in a given compound.
Molecular formula on the other hand tells us the actual number of atoms of each element a compound or a molecules has. Molecular formula is calculated from the empirical formula and the molecular mass of a compound.

Answer:

C₄H₈O₂ = C₂H₄O

C₄H₁₂O₄ = CH₃O

C₂H₁₀O₂ = CH₅O

Explanation:

1) C₄H₈O₂ = C₂H₄O

The smallest subscript is 2. So dividing each subscript by 2 we get,

C₄/₂H₈/₂O₂/₂ = C₂H₄O

2) C₄H₁₂O₄ = CH₃O

The smallest subscript is 4. So dividing each subscript by 4 we get,

C₄/₄H₁₂/₄O₄/₄ = CH₃O

3) C₂H₁₀O₂ = CH₅O