What is the KE of a 1 kg ball traveling at 30 meters per second?

Answers

Answer 1

Answer: KE = 1/2 mass times speed-squared KE = 1/2 (1) (900) = 450 joules

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The table below shows the number of hours some business people in two states spend in meetings each week:State A 21 23 24 22 24 25 23 23 22 State B 24 22 20 23 23 50 20 46 21 Part A: Create a five-number summary and calculate the interquartile range for the two sets of data. Part B: Are the box plots symmetric? Justify your answer.
Pls help this is due soon If the discriminate of a quadratic equation is negative___.a.there will be 2 solutions either of which may be positive or negativeb.there will be only one solutionc.there will be 2 solutions but they will both be negatived.there will be 2 solutions but they will both be positivethee.none of these

Mr. Li records the measures of the lengths of his students’ handprints. The lengths, in centimeters, are shown in the table.14.0 , 11.5 , 12.1 , 16.2 , 13.5 , 14.3 , 16.8
12.4 , 13.7 , 12.0 , 14.7 , 15.2 , 11.9 , 15.6
13.8 , 14.2 , 12.5 , 15.0 , 16.0 , 13.1 , 11.7

If the class creates a histogram of the data in the table, how many students are in the range 12 cm to 13.9 cm?

1) 3
2) 4
3) 7
4) 8

Answers

The correct answer is:

4) 8

Explanation:

We want to find the frequency of this range. To do this, we count how many values fall between 12.0 and 13.9. There are 8 total values that do this, so the answer is 8.

In the given data set, there are 7 values in the given range.

How many students are in the range 12 cm to 13.9 cm?

Here we just need to find the number of values between 12cm and 13.9 cm, from the given table, these are:

12.1 cm, 13.5 cm, 12.4 cm, 13.7 cm, 13.8 cm, 12.5 cm, 13.1 cm

So there are 7 values in the given range, which means that 7 students are in the range of 12cm and 13.9cm.

Then the correct option is the third one.

If you want to learn more about data sets:

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An arithmetic sequence is given below.-4, -10, -16, -22, ...
write an explicit formula for the Nth term aN.

Answers

Answer:

an=−6n+2

Step-by-step explanation:

First, you need to identify the first term and the common difference of the sequence. The first term is the value of the first element, which is -4. The common difference is the amount that is added or subtracted to each term to get the next one, which is -6 in this case. You can find it by subtracting any two consecutive terms, such as -10 - (-4) = -6 or -16 - (-10) = -6.

Next, you need to use the standard explicit formula for an arithmetic sequence, which is:

an=a1+d(n−1)

where an is the Nth term, a1 is the first term, d is the common difference, and n is any term number.

Finally, you need to substitute the values of a1 and d that you found in the first step into the formula. This gives:

an=−4+(−6)(n−1)

This is the explicit formula for the Nth term aN of the given arithmetic sequence. You can simplify it further by expanding and combining like terms:

an=−4−6n+6

an=−6n+2

Jill Barkely obtained a 25-year, $460,000 mortgage loan from University Savings and Loan Association with 6% interest. The monthly payment is $2,962.40. For the first payment, find the interest to the nearest cent.

Answers

Have you considered calculating it directly? $2,962.40*(0.06/12)
If you do that then your answer would be 14.81...
Hope this helps... :)

HOW CAN YOU MAKE 7,5,6,AND 3 EQUAL 75 USING PARENTHESIS.

Answers

$(7+5)*6+3=12*6+3=72+3=\boxed{75}$

One possible answer is:

5((7x3)-6).

Explanation:

75 ends in 5, so it is divisible by 5. 75/5 = 15. If we can arrange 7, 6 and 3 some way to make 15, we can use this multiplied by 5.

7x3=21, and 21-6=15; this gives us what we need!

5(21-6) = 75; 21 = 3x7, so 5((3x7)-6).

In a function you cannot have to of the same x values right?

Answers

Yes, in a function you cannot have two different images for the same x.

Because if an x has more than one image, you couldn't tell what is the value of the image given that x.

What are the values of x in the equation x(x-6)=4(x+6)

Answers

$x(x-6)=4(x+6)\ \ \ |use\ distributive\ property\ a(b+c)=ab+ac\n\nx(x)+x(-6)=4(x)+4(6)\n\nx^2-6x=4x+24\ \ \ \ |subtract\ 4x\ and\ 24\ from\ both\ sides\n\nx^2-10x-24=0\n\nx^2-12x+2x-24=0\n\nx(x-12)+2(x-12)=0\iff(x-12)(x+2)=0\n\ntherefore\n\nx-12=0\ or\ x+2=0\n\nAnswer:\boxed{x=12\ or\ x=-2}$

        x(x - 6) = 4(x + 6)
    x(x) - x(6) = 4(x) + 4(6)
     x² - 6x = 4x + 24
         - 4x - 4x
     x² - 10x = 24
x² - 10x - 24 = 24 - 24
x² - 10x - 24 = 0
x = -(-10) +/- √((-10) - 4(1)(-24))
   2(1)
x = 10 +/- √(100 + 96)
   2
x = 10 +/- √(196)
2
x = 10 +/- 14
2
x = 5 + 7
x = 5 + 7 U x = 5 - 7
x = 12    x = -2
The values of x in the equation is either equal to 12 or -2.

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