The weight of an object is the force it experience by the gravitational pull of the planet. The gravitational pull by earth is greater than that from moon. This leads to greater weight in earth than in moon.
Gravitational force is a kind of force by which an object attracts other objects into its center of mass. The force exerted between the objects depends on the mass and distance between them.
Earth exerts a gravitational pull to every objects on its surface and that's why we are standing on the ground. We experience a weight downwards due to this force.
The acceleration due to gravity in earth = 9.8 m/s²
g in moon = 1.63m/s².
then weight = m g
the weight of a 10 kg iron bar in earth is 98 N and that in moon will be 16.3 N.
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Answer:
The decrease in the downward force that a mass of iron can exert on the moon versus the force it exerts on earth is due to:
Explanation:
To recognize the calculation within the statement, you must know that the Newton unit is equal to:
And that the gravities of the Earth and the Moon are:
Finally, you must know the force formula (since we are talking about a descending force):
Since the mass in both cases is the same (10 kilograms), the variation in acceleration will provide different values of descending force, as shown below, replacing the values:
As you can see, when it comes to force, the less acceleration (in this case less gravity), the lower the downward force will be with a mass of equal weight.
Calculate:
(a) the time to reach maximum height
(b) the maximum height above the base of the cliff reached by the
projectile
(c) thetotal time it is in the air
(d) the horizontal range of the projectile.
Answer:
a) 9.99 s
b) 538 m
c) 20.5 s
d) 1160 m
Explanation:
Given:
x₀ = 0 m
y₀ = 49.0 m
v₀ = 113 m/s
θ = 60.0°
aₓ = 0 m/s²
aᵧ = -9.8 m/s²
a) At the maximum height, the vertical velocity vᵧ = 0 m/s. Find t.
vᵧ = aᵧ t + v₀ᵧ
(0 m/s) = (-9.8 m/s²) t + (113 sin 60.0° m/s)
t ≈ 9.99 s
b) At the maximum height, the vertical velocity vᵧ = 0 m/s. Find y.
vᵧ² = v₀ᵧ² + 2aᵧ (y − y₀)
(0 m/s)² = (113 sin 60° m/s)² + 2 (-9.8 m/s²) (y − 49.0 m)
y ≈ 538 m
c) When the projectile lands, y = 0 m. Find t.
y = y₀ + v₀ᵧ t + ½ aᵧ t²
(0 m) = (49.0 m) + (113 sin 60° m/s) t + ½ (-9.8 m/s²) t²
You'll need to solve using quadratic formula:
t ≈ -0.489, 20.5
Since negative time doesn't apply here, t ≈ 20.5 s.
d) When the projectile lands, y = 0 m. Find x. (Use answer from part c).
x = x₀ + v₀ₓ t + ½ aₓ t²
x = (0 m) + (113 cos 60° m/s) (20.5 s) + ½ (0 m/s²) (20.5 s)²
x ≈ 1160 m
B. less than
C. the same as
D. none of the above
The gravitational forces are the same. (C).
1 kg is 1 kg. It always has the same weight, no matter whether it's made of kryptonite, concrete, or chicken soup.
If I sealed the kg of lead and the kg of marshmallows into two different boxes, you couldn't tell any difference.
It reflects a lot of light, transmits almost no light, and absorbs some light.
B.
It reflects some light, transmits some light, and absorbs no light.
C.
It reflects all light, transmits all light, and absorbs some light.
D.
It reflects almost no light, transmits almost no light, and absorbs almost no light.
Lots of points:)