615 N
B.
10.9 N
C.
615 m/s
D.
10.9 m/s
The kinetic energy (KE) is calculated using the formula KE = 1/2 * m * v^2, resulting in a kinetic energy of 1.0 Joule for a 2.0 kg guinea pig moving at a speed of 1.0 m/s.
The kinetic energy (KE) of an object in motion is determined by the formula: KE = 1/2 * m * v^2, where m is the mass and v is the velocity. For the guinea pig in question, with a mass (m) of 2.0 kg and a velocity (v) of 1.0 m/s, the calculation is as follows:
KE = 1/2 * 2.0 kg * (1.0 m/s)^2
KE = 1/2 * 2.0 kg * 1.0 m^2/s^2
KE = 1.0 kg * 1.0 m^2/s^2
KE = 1.0 Joule
Therefore, the kinetic energy of the 2.0 kg guinea pig running at a speed of 1.0 m/s is 1.0 Joule.
The kinetic energy for the above data is 1.0000 J.
/
c
m
3
.
Part A
Part complete
What is this value in kilograms per cubic meter?
1.35×104
kg/m3
k
g
/
m
3
If the density of mercury is 13.5 g/cm³ in the gram per centimeter cube unit, then the density of the mercury would be 1.35×10⁴ in the kilograms per cubic meter
It can be defined as the mass of any object or body per unit volume of the particular object or body. Generally, it is expressed as in gram per cm³ or kilogram per meter³.
By using the above formula for density
ρ = mass / volume
As given in the problem If the density of mercury is 13.5 g/cm³ in the gram per centimeter cube unit then we have to convert its value into kilograms per cubic meter.
1000 grams = 1 kilogram
1 gram = 1/1000 kilograms
=1×10⁻³ kilograms
10⁶ cubic centimeter = 1 cubic meter
1 cubic centimeter = 1/10⁶ cubic meter
= 1× 10⁻⁶ cubic meter
Given the density of the mercury 13.5 g/cm³
13.5 g/cm³ = 13.5 ×10⁻³ kilograms / 1× 10⁻⁶ cubic meter
= 1.35×10⁴ kilograms / cubic meter
Thus, we converted the density of mercury is 13.5 g/cm³ into 1.35×10⁴ kilograms / cubic meter
To learn more about density from here, refer to the link;
#SPJ2
Answer:
DO IY.T
Explanation:
current in the flashlight?
Answer:
3 A
Explanation:
The relationship between voltage, current and resistance in a conductor is expressed by Ohm's law, which states that:
where:
V is the potential difference across the conductor
R is the resistance of the conductor
I is the current flowing through it
In this problem, for this flashlight we have:
V = 90 V is the potential difference
is the resistance of the flashlight
Solving for I, we find the current: