In rectangle KLMN, KM =6x + 16, and LM =49. find the value of x
Answers
Also, the diagonals in a rectangle have equal length.
KM and LN are the diagonals and they are equal by definition.
So, we can write the equation: KM=LM
6x+16=49
6x=49-16
6x=33
x=5.5
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The value of x in expression cos(2x-1) = sin(3x+6) is 17.
cos(2x-1) = sin(3x+6)
let
a = 2x - 1
b = 3x + 6
Therefore,
cos a = sin b
Therefore, a and b are complimentary.
What is complimentary angle?
Complimentary angles are angles that sum up to 90 degrees. Therefore,
2x - 1 + 3x + 6 = 90
2x + 3x - 1 + 6 = 90
5x + 5 = 90
5x = 90 - 5
5x = 85
x = 85 / 5
x = 17
learn more on trigonometry here: brainly.com/question/2193114
5x + 5 = 90
5x = 90 - 5
5x = 85
x = 85/5
x = 17°
Answers
- 6 * x - 10 > 14 + 2 * x
- 6 * x - 2 * x - 10 > 14
- 8 * x - 10 > 14
- 8 * x > 24 /(-8)
x < 24 / (-8)
x < - 3
The correct missing step would be - 8 * x - 10 > 14.
Answers
Hey!
The area of the board is 60,000 centimeters.
1 meter = 100 centimeters
2 meters = 200 centimeters
3 meters = 300 centimeters
300 × 200 = 60,000
One cup covers 1,000 centimeters. To cover 60,000 centimeters, divide 60,000 by 1,000.
That means Arella needs 60 cups
Since the paint covers a certain number of square centimeters and the board's dimensions are given in meters, we need to use one single unit.
Let's convert the measurements in meters to centimeters and work with square centimeters.
The board measures 3 meters by 2 meters.
There are 100 cm in a meter.
3 m = 300 cm
2 m = 200 cm
area of rectangle = length * width
area of rectangle = 300 cm * 200 cm = 60,000 cm^2
The area of the rectangle is 60,000 cm^2
One cup covers 1,000 cm^2.
How many times the area of 1,000 cm^2 needs to be covered?
60,000 cm^2 is how many times 1,000 cm^2?
We use division to answer that question.
(60,000 cm^2)/(1,000 cm^2) = 60
60,000 cm^2 is 60 times 1,000 cm^2.
Since 1 cup covers 1000 cm^2, and Arella needs to cover 60 times that area, Arella needs 60 times the paint contained in 1 cup, so the answer is 60 cups.
Answer: Arella needs 60 cups of paint.
Answers
you can divide both sides by a common factor, in this case 2