On a string of lights,for every 6 green lights, there are 4 white.If there are 30 green lights, how many white lights are there?

Answers

Answer 1

Answer: I got the answer by setting up a little table of 6 and 4 and got 24.
Hope this is helpful. :)

Answer 2

Answer: 6 green = 4 white

There are five 6s in 30

So 5x4= 20

So 30 green 20 white

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Math question down below

Answers

Do 6.5” divided by 5 to find the slope . Then plot each point and

6d 1 = 15-d I really don't understand thisssss and my teacher won't help

Answers

You required to find the value of d.
Always remember the concept that if you transpose "+" sign to the other side, it becomes "-" sign, and vice versa. Make sure that you arrange the like terms and constants. Solving the equation,
6d + 1 = 15 - d
6d + d = 15 - 1
7d = 14
d = 14/7 = 2

When transposing a multiplication, you divide it to the other side.

Verifying the solution,
6(2) + 1 = 15 - 2
12 + 1 = 13
13 = 13

If y=-4 when x=10, determine y when x=5.

Answers

$y=-4 \n x=10 \n \ny =? \n x=5 \n ---------------- \n {\left \{ {{y=-4} \atop {x=10}} \right. }/ :2 \n \n {\left \{ {{\boxed{y=-2} \atop {x=5}} \right. } \n \n \text{Answer: y=-2}$

What is the common difference between the elements of the arithmetic sequence below?–18, –22.5, –27, –31.5, –36

Answers

Answer:

sorry this is late but the answer is -4.5.

Step-by-step explanation:

I got this right on edge! Please give this a like and mark brainliest!

The sequence:

-18 , -22.5 , -27 , -31.5 , -36

Common difference:

(-18 - -22.5) = (-22.5 - -27) = (-27 - -31.5) = (-31.5 - -36) = 4.5 ( When two minuses come together, they make a plus. So difference is certainly the positive next number - positive previous number to give 4.5)

Common difference = 4.5

Type of the sequence: Arithmetic sequence.

Match each scientific notation with the appropriate number

Answers

Answer:

wheres the answer choices

Mrs. Harrison used 16 ounces of dark chocolate while baking. She used 2/5 of the chocolate to make some frosting and used the rest to make brownies. How much more chocolate did Mrs. Harrison use in the brownies than in the frosting

Answers

¹⁶/₅ or 3 ¹/₅ or 3.2 ounces.

Further explanation

Given:

Mrs. Harrison used 16 ounces of dark chocolate while baking.
She used ²/₅ of the chocolate to make some frosting.
She used the rest to make brownies.

Question:

How much more chocolate did Mrs. Harrison use in the brownies than in the frosting?

The Process:

From the information above, we made a suitable diagram as follows:

$\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot} = 16 \ ounces$

Hence, one part equal to $(16)/(5) \ ounces$ .

She used $(2)/(5)$ of the chocolate to make some frosting, meaning two of five parts of the chocolate.

$\boxed{\cdot}\boxed{\cdot}$

And she used the rest, that is, $(3)/(5)$ of the chocolate to make brownies, meaning three of five parts of the chocolate.

$\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}$

Finally, let us find out how much more chocolate did Mrs. Harrison use in the brownies than in the frosting. Before that, prepare in the form of a fraction of the part in question.

$\boxed{ \ = (3)/(5) - (2)/(5) \ }$

$\boxed{\boxed{ \ = (1)/(5) \ }}$ or one of five parts of the chocolate.

We declare this fraction into ounces by multiplying it by 16 ounces.

$\boxed{ \ = (1)/(5) * 16 \ ounces \ }$

$\boxed{\boxed{ \ (16)/(5) \ or \ 3(1)/(5) \ or \ 3.2 \ ounces \ }}$

Thus Mrs. Harrison used 3.2 ounces more chocolate in brownies than in the frosting.

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Keywords: Mrs. Harrison, used 16 ounces, dark chocolate, while baking, she used 2/5, to make some frosting, and used the rest to make brownies. How much more chocolate did Mrs. Harrison use in the brownies than in the frosting

1/5 bc 5/5=total. So u would do 5/5-3/5= 2/5. then 3/5-2/5= 1/5

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