What is the equation of the line, in slope-intercept form, that passes through (3, -1) and (-1,5)? What is the equation of the line, in standard form, that passes through (4, -3) and is parallel to heline whose equation is 4x + y - 2 = 0?

Given the line 2x - 3y - 5 = 0, find the slope of a line that is perpendicular to this line.

Answers

Answer 1

Answer: $m = (y_(2) - y_(1))/(x_(2) - x_(1)) = (5 - (-1))/(-1 - 3) = (5 + 1)/(-4) = (6)/(-4) = (3)/(-2) = -1(1)/(2)$
y - y₁ = m(x - x₁)
y - (-1) = -1¹/₂(x - 3)
y + 1 = -1¹/₂(x) + 1¹/₂(3)
y + 1 = -1¹/₂x + 4¹/₂
      - 1 - 1
   y = -1¹/₂x + 3¹/₂

4x + y - 2 = 0
      + 2 + 2
       4x + y = 2
4x - 4x + y = -4x + 2
   y = -4x + 2
   y - y₁ = m(x - x₁)
      y - (-3) = -4(x - 4)
       y + 3 = -4(x) + 4(4)
   y + 3 = -4x + 16
       - 3 - 3
   y = -4x + 13

2x - 3y - 5 = 0
       + 5 + 5
2x - 2x - 3y = -2x + 5
   -3y = -2x + 5
      -3    -3
      y = ²/₃x - 1²/₃
   y - (-3) = -1¹/₂(x - 4)
      y + 3 = -1¹/₂(x) + 1¹/₂(4)
      y + 3 = -1¹/₂x + 6
      - 3     - 3
      y = -1¹/₂x + 3

Answer 2

Answer:

its b because the others are incorrect

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theanswer is4thoption

the answer is the last one
hope that helps

Help i need help with this question.

Answers

Umm where’s the question cause that’s just a picture

Help plzzz ill give extra points ‼️‼️

Answers

C is the answer I believe

Solve the proportion. If necessary, round to the nearest hundredth. 9/(y +1) = 18/54 *22

18

30

26

Answers

Answer: y=26

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