PHYSICS HIGH SCHOOL

An object is placed at 0 on a number line. It moves 3 units to the right, then 4 units to the left, and then 6 units to the right. The displacement of the object is

Answers

Answer 1
Answer:

The correct answer is: +5

Explanation:

An object is placed at 0; it means:

Initial position of the object = 0.

Now it moves to 3 units to right, so keeping the standard cartesian coordinate system in mind (in right right x-axis is positive and left x-axis is right), the new position of the object will be +3.

Object now moves 4 units to the left, it means +3 - 4 = -1; object is at the position -1.

Object then moves 6 units to the right, therefore,

Final position of the object = -1 + 6 = +5.

Displacement = Final position - Initial position

Displacement = +5 - 0 = +5
Answer 2
Answer:

Answer:

Explanation:

The correct answer is: +5

Explanation:

An object is placed at 0; it means:

Initial position of the object = 0.

Now it moves to 3 units to right, so keeping the standard cartesian coordinate system in mind (in right right x-axis is positive and left x-axis is right), the new position of the object will be +3.

Object now moves 4 units to the left, it means +3 - 4 = -1; object is at the position -1.

Object then moves 6 units to the right, therefore,

Final position of the object = -1 + 6 = +5.

Displacement = Final position - Initial position

Displacement = +5 - 0 = +5

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A body moving with a velocity of 20m/s begins to accelerate at 3 m/s 2 . How far does the body move in 3 seconds

Answers

Given v_in = 20 m/s and a = 3 m/s2, assuming that the bodymoves at constant acceleration, the motion is modeled by the equation:

s(t) = (v_in)t + (1/2)a(t^2)

where s(t) is the distance traveled

substituting the given,

s(t) = 20t + (3/2)(t^2)

at t = 3

s(t) = 20(3) + (3/2)(3)^2

= 73.5 m

If a substance is heated and then cooled off but remains as the original substance a _____ change has occurred.A) physical
B) chemical
C) structural
D) physical and chemical

Answers


I'm going to say physical change

explanation:

The substance as you said did not change therefore a chemical change could not have happened because they result in a new substance meaning one or multiple new substances could have been created from the chemical change. With a physical change the only thing that changes is the outward appearance.

example of physical change:  water changing into ice. The frozen water is composed of the same elements as the liquid water.

Hopefully this helped and good luck.
I'm not a physicist, or an expert, but physical and structural both have a similar meaning, they both relate to appearances, but the question says "but remains as the original substance" so, if it isn't a visible change, then the only good answer left is a chemical change, hope this helps

Which mathematical relationship best describes a graph of gravitational field strength versus distance? (one of the 3 pictures attached or none of the above?)

Answers

The gravitational force between two masses is proportional to

                               (mass-1) x (mass-2) / (the distance between them)-squared

Do you see (distance-squared) in the denominator there ?

That steers you straight to the function [ y proportional to 1/x² ] ... in the middle.
gravitationnal field between two objets = k.m1.m2/d² 
none of the above
the graph is something like that

The density of table sugar is 1.59 g/cm3. What is the volume of 7.85 g of sugar?

Answers

(7.85g )/(1.59 (g)/( cm^(3) ) ) = 4.937 cm^(3)

you apply the same amount of heat to five grams of substance a and five grams of substance b. the temperature of both substances increases by the same amount. what can you conclude?

Answers

From the given statement, it can be concluded that both substance a and substance b has the same heat capacity or thermal capacity. It can also be possible that both the substances are same and so their heat capacity or thermal capacity is also same. Thermal capacity of any substance is amount of energy that is required to raise the temperature of the substance through a specific range. Under normal circumstances this range varies from substance to substance based on the type.


(plato answer) The heat capacity of substance A is equal to the heat capacity of substance B.

You put the wet leaves in the container and turn the crank to spin off the water. The radius of the container is 13.2 cm. When the cylinder is rotating at 1.63 revolutions per second, what is the magnitude of the centripetal acceleration at the outer wall?

Answers

Answer:

centripetal acceleration(a_(c))=13.8m/s^(2)

Explanation:

convert 1.63rev/sec to rpm by multiplying by 60

= 1.63*60=97.8rpm

Convert this to rad/sec

1rpm =π/30 rad/sec

97.8rpm = 97.8 * (π/30 rad/sec)

              =10.25rad/sec

linear velocity=  angular velocity *radius

radius =13.2cm=13.2/100=0.132m

v=rω

v= 0.132*10.25

v=1.35m/s

centripetal acceleration = (v^(2) )/(r)

a_(c)=(1.35^(2) )/(0.132)

a_(c)=13.8m/s^(2)

Answer:

a_(c) = 13.8 m/s².

Explanation:

The acceleration centripetal a_(c) is given by:

a_(c) = (v^(2))/(r)    (1)

where v: is the tangential speed and r: is the container radius

The tangential speed is equal to:

v = \omega \cdot r   (2)

where ω: is the angular velocity

Since 1 revolution is equal to 2π rad, the velocity (equation 2) is:

v = 1.63 (rev)/(s) \cdot (2\pi rad)/(1rev) \cdot 0.132m = 1.35m/s  

Now, by entering the velocity value calculated into equation (1) we can find the acceleration centripetal:

a_(c) = ((1.35m/s)^(2))/(0.132m) = 13.8m/s^(2)

I hope it helps you!    
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