Find three consecutive odd numbers whose sum is 303
Answers
Answer 1
Answer:
%2B(n%2B4)%3D303%5C%5C%5C%5C3n%2B6%3D303%5C%5C%5C%5C3n%3D303-6%5C%5C%5C%5C3n%3D297%5C%20%5C%20%5C%20%5C%20%2F%3A3%5C%5C%5C%5Cn%3D99%5C%5C%5C%5CAnswer%3A99%3B%5C%20101%3B%5C%20103.)
Answer 2
Answer:
99 + 101 + 103 = 303
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2. tan -105 degrees
Answers
Hello,
1)
tan (a-b)=(tan a - tan b)/(1+tan a tan b)
15=45-30
tan 45°= (√2/2)/(√2/2)=1
tan 30°=(1/2)/(√3/2)=√3/3
tan (45°-30°)= (1-√3/3)/(1+1*√3/3)=(3-√3)/(3+√3)=(3-√3)²/6=2-√3
tan (-105°)=tan (75°)= tan (60°+15°)=(tan 60+tan15°)/(1-tan 60°*tan 15°)
tan 15°=2-√3
tan 60°=√3°
tan (-105°)=(√3+2-√3)/(1-√3*(2-√3))=2/(1-2√3+3)=1/(2-√3)=2+√3
1)
tan (a-b)=(tan a - tan b)/(1+tan a tan b)
15=45-30
tan 45°= (√2/2)/(√2/2)=1
tan 30°=(1/2)/(√3/2)=√3/3
tan (45°-30°)= (1-√3/3)/(1+1*√3/3)=(3-√3)/(3+√3)=(3-√3)²/6=2-√3
tan (-105°)=tan (75°)= tan (60°+15°)=(tan 60+tan15°)/(1-tan 60°*tan 15°)
tan 15°=2-√3
tan 60°=√3°
tan (-105°)=(√3+2-√3)/(1-√3*(2-√3))=2/(1-2√3+3)=1/(2-√3)=2+√3
x + 3y = 5
Answers
Solve and the solution would be (-1, 2)
x value = -1
x value = -1
B. n || m
C. ℓ || k
D. ℓ || m