MATHEMATICS HIGH SCHOOL

Which is not a theorem or postulate used to prove triangles similar? SSS
SAS
AA
SSA

Answers

Answer 1
Answer: there\ are\ 3\ postulates\ of\ triangles\ similarity:\n -Side Side Side\ (SSS) -\corresponding\ sides\ are\n all\ in\ the\ same\ proportion\n\n -AngleAngleAngle\ (AAA)-\ All\ 3\ corresponding\n angles\ are\ the\ same\n\n -SideAngleSide\ (SAS)\ - Two\ pair\ of\ sides\ are\ in\ the\n same\ proportion\ and\ two\ angles\ are\ the\ same.\n\n Answer: \ AA\ and\ SSA\ are\ not\ postulates\ for\ triangle\ similarity.

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Answers

When adding functions with the same base you simply add the exponents so:
a^(1/2)*a^(x) = a^(1)
(1)/(2)+x = 1
x = (1)/(2)

Thus to finish the equation you would say a^(1/2)

Help me with this.. thanks

Answers

Answer:

Attachment 1 :-   x = 3/2

Attachment 2 :-  m + r = 154°

Step-by-step explanation:

Attachment 1 :-

9^(^2^-^x^) = 3\n=> 3^2^(^2^-^x^) = 3\n

As the base 3 is same on both the sides , cancel the base 3 from both left & right side of eqn. After that we will get:-

2(2 - x) = 1\n=> 2 - x =(1)/(2) \n=> x = 2 - (1)/(2) = (3)/(2)

Attachment 2 :-

PQR is a straight line . It's given that m + n = 110°

But we know that m + n + r = 180° ..............eqn.1

So substituting the value of m+n in eqn.1 gives :-

m+n+r = 180°

=> r + 110° = 180°

=> r = 180° - 110°

       = 70°

It's also given that n+r = 96°

So putting the value of r in the above gives ,

n+r = 96°

=> n + 70° =96°

=> n = 96° - 70°

        = 26°

Putting the value of n in eqn.1 gives

m + n = 110°

=> m + 26° = 110°

=> m = 110° - 26°

        = 84°

So m + r = 84° + 70° = 154°

Find the magnitude of theresultant vector.
(-9, -2) w
(14,7) v
R=[?]
Round to the nearest hundredth.

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