Fathi wants to print out a PDF document that is 48484848 pages long. To save paper, he decides to print on both sides of each sheet and to print two pages on each side of the sheet. How many sheets of paper will he need?
Answers
48, 484, 848 ÷ 2 = 24, 242, 424.
This is because Fathi is using one paper for two pages.
Therefore, that is why you divide 48, 484, 848 and 2.
Related Questions
The probability that a city bus is ready for service when needed is 77%. The probability that a city bus is ready for service and has a working radio is 65%. Find the probability that a bus chosen at random has a working radio given that it is ready for service. Round to the nearest tenth of a percent. (Hint: Divide)
Is y=5x+4 proportional?
Sally got a new phone plan that includes limited data of 10 GB for $85, tax included. She has to pay $15 for each additional GB used if she goes over her 10 GB allowed. Part A: Write an equation to describe her data plan where x represents each additional GB used.
What us the length of the altitude of the equilateral triangle below
Answers
y = 2|3(x - 1)| - 4
y = 6|x - 1| - 4
The graph is a V shaped graph with vertex at (1, -4), x-intercepts at (1/3, 0) and (5/3, 0) any y intercept at (0, 2).
Answers
If you get 20% of 13,666 you get 819.96
If you get 20% of 13,667 you get 820.02
and if you get 20% of 13,665 you get 819.90
so if they want you to round the cents then 13,666 would be your answer because when you do this ----> 13,666X.06=819.96 you might have to round the 6 to 9 which makes 819.96 into 820 so answer is B
Answers
4 * 4 (or
16 * 4 *4 *4 *4 *4
16384 people will know the art of quilling
(c- 2,y) or (2- c,y)
Answers
Answer:
option (1) is correct.
point (c-2, y) lies on the graph of .
Step-by-step explanation:
Given function also point (2+ c,y) is on the graph of f(x) ,
We have to find out of given point which point will also be on the graph of f(x).
Consider the given function
can be rewritten
Now we substitute the given point (2+ c, y) in the function given ,
we have,
put for x as 2+c , we have,
Solve, we get
Thus, both point (2+c, y) and (c-2, y) lies on the graph of
Thus, option (1) is correct.
Final answer:
To determine whether the point (2+c, y) being on the graph of f(x) implies that the point (c-2, y) or (2-c, y) will also be on the graph of f(x), we need to substitute each point into the function and check if they satisfy the equation.
Explanation:
In this question, we are given the function f(x) = x(x-4). We need to determine whether the point (2+c, y) being on the graph of f(x) implies that the point (c-2, y) or (2-c, y) will also be on the graph of f(x). To verify this, we will substitute the given point (2+c, y) into the function and see if it satisfies the equation. Let's break it down step by step:
- Substitute the x-coordinate of the given point (2+c, y) into the function f(x).
- Simplify and solve the resulting equation for y.
- Substitute the x-coordinate of the points (c-2, y) and (2-c, y) into the function f(x) to check if they satisfy the equation.
- Based on the results, determine whether the given point implies that the other two points will also be on the graph of f(x).
Learn more about Graphing functions here:
#SPJ11
Answers
t= $0.75
it would be:
price=6.95 + 0.75 • (<--multiplication sign) amount of topings
Answers
60 feet above the water. So what you're really asking is: Calculate whether
the stone can reach 40 feet above Henry, and we can forget about the creek ?
Call Henry's elevation zero, and the height of the stone at any time after
the toss 'H'.
Way back among the pages in your Physics book that are clean and shiny
because they have never yet been exposed to air or sunlight, you will find
the formula for the height of an object in free-fall:
Height = H₀ + V₀t + 1/2 A t²
H₀ = the object's height when it was released
V₀ = the object's speed when it was released, negtive if downward
A = the object's acceleration, negative if downward
t = time since the object was released
In the case that involves Henry on the bridge . . .
H₀ = 0
V₀ = +50 ft/sec
A = -32 ft/sec² (acceleration due to gravity)
We want to know if the height of the object can ever be +40 feet.
We can plug all the numbers into the equation, and solve it. Since the equation
is written in terms of ' t ', any solution we get will be a 'time'. That's not what
we're looking for, but if there's any real solution, then we'll know that it's possible.
40 = 50t + 16t²
Subtract 40 from each side:
16t² + 50t - 40 = 0
Just to make the numbers more manageable, divide each side by 2 :
8t² + 25t - 20 = 0
Plug this into the quadratic formula:
t = (1/16) x (-25 plus or minus the square root of [625 - 640] )
Do you see that 'square root of -15 in there ?
The ' -15 ' is called the 'discriminant' of our quadratic equation, and
since it's negative, our equation has no real solutions ... there's no
such thing as the real square root of a negative number.
So the answer to the question is: No. The stone never reaches a height
of 40 feet above Henry, or 60 feet above the creek.
Whew!
===============================================
A slightly easier way to do it:
Henry throws the stone upward at 50 ft/sec.
The acceleration of gravity is 32 ft/sec² downward.
The stone keeps rising for (50/32) = 1.5625 second, until its upward speed
has shrunk to zero, and then it starts falling.
How high is it when it stops rising ?
Its upward speed was 50 when Henry tossed it, and zero when it stopped rising.
Its average speed on the way up was (1/2)(50 + 0) = 25 ft/sec upward.
It has that average speed for 1.5625 seconds.
How far does it climb in that time ?
H = (25 ft/sec) x (1.5625 sec) = 39.0625 feet.
That's pretty close, but not quite 40 feet above Henry.
So the answer to the question is: No.
K.E.=P.E(at the max height)
1/2mv^2=mgh
m cancels out,
or, h=1/2v^2/g
or, h=1/2*50*50/32
or, h=39 ft (approx.)
As he is 20 ft above water so total height the stone an reach 39+20=59 ft.
Hence, it can't reach 60 ft over the creek.