Matthew used 1/5 of a box of flour for cooking and 3/4 of the remainder to make bread. The rest of the flour was packed equally into 5 containers. What fraction of the total amount of flour was in each container?

Answer:

Number of Adult tickets sold = 420

Number of Students tickets sold = 360

Step-by-step explanation:

Given as ,

Number of adult ticket + Number of Students tickets = 780  

Each Adult ticket cost = $8

Each Student ticket cost = $3

Total of ( Adult ticket cost + Student ticket cost) = $ 4,440

i.e

A + S = 780         ....1

And 8A + 3S = 4440         .....2

Solve eq 1 and 2

Or, 8A + 3S = 4440

     3A + 3S = 2340

Or, (8A + 3S) - (3A + 3S) = (4440 - 2340)

or,  5A = 2100

So, A = 420    

Now put this A value in eq 1

So 420 + S = 780

Or, S = 780 - 420

So , S = 360  

Hence The Number of Adult tickets sold = 420

And     The Number of Student tickets sold = 360

Answer:

Jasmine could have 84 bouquets with 1 flower in each,28 bouquets with 3 flower in each,12 bouquets with 7 flower in each or 4 bouquets with  21 flower in each.

Step-by-step explanation:

The total number of flowers that jasmine has to make bouquets is 84.

We need to note that she want to use all the flowers.

Now let us write down all factors of 84.

84= 1 * 84  ....(1)

   = 2 * 42 ....(2)

   = 3 * 28 ....(3)

   = 4 * 21  ....(4)

   = 6 * 14 .....(5)

   = 7 * 12  ....(6)

Now all we need is odd number of flowers in each bouquet,i.e,

All the numbers written in the right hand side of the above 1 to 6

numbered equations are factors of 84.

Since Jasmine wanted no flowers to be wasted so we can assume that number of flowers in each bouquet must be an odd factor of 84.

Therefore, odd factors of 84 are 1,3,7,21.

So Jasmine could have 84 bouquets with 1 flower in each,28 bouquets with 3 flower in each,12 bouquets with 7 flower in each or 4 bouquets with  21 flower in each.

Answer:

the answer is 7

Step-by-step explanation:

The greatest common factor of 8 and 9 is 1. The largest positive integer that divides two numbers without producing a remainder is known as the greatest common factor (GCF).

We have the numbers 8 and 9 in this instance. We must uncover the elements that both numbers have in common and choose the biggest one to determine their GCF. In comparison to the factors of 9, which are 1, 3, and 9, the factors of 8 are 1, 2, 4, and 8.

The highest positive integer that divides both 8 and 9 is 1, hence the only factor they have in common is that. Therefore, 1 is the number that connects 8 and 9 most frequently.

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Answer:The factors of 8 are: 1, 2, 4, 8

The factors of 9 are: 1, 3, 9

Then the greatest common factor is 1.

Step-by-step explanation:How to Find the Greatest Common Factor (GCF)

There are several ways to find the greatest common factor of numbers. The most efficient method you use depends on how many numbers you have, how large they are and what you will do with the result.

Factoring

To find the GCF by factoring, list out all of the factors of each number or find them with a Factors Calculator. The whole number factors are numbers that divide evenly into the number with zero remainder. Given the list of common factors for each number, the GCF is the largest number common to each list.

Example: Find the GCF of 18 and 27The factors of 18 are 1, 2, 3, 6, 9, 18.

The factors of 27 are 1, 3, 9, 27.

The common factors of 18 and 27 are 1, 3 and 9.

The greatest common factor of 18 and 27 is 9.

Example: Find the GCF of 20, 50 and 120

The factors of 20 are 1, 2, 4, 5, 10, 20.

The factors of 50 are 1, 2, 5, 10, 25, 50.

The factors of 120 are 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120.

The common factors of 20, 50 and 120 are 1, 2, 5 and 10. (Include only the factors common to all three numbers.)

The greatest common factor of 20, 50 and 120 is 10.Prime Factorization

To find the GCF by prime factorization, list out all of the prime factors of each number or find them with a Prime Factors Calculator. List the prime factors that are common to each of the original numbers. Include the highest number of occurrences of each prime factor that is common to each original number. Multiply these together to get the GCF.

You will see that as numbers get larger the prime factorization method may be easier than straight factoring.

Example: Find the GCF (18, 27)

The prime factorization of 18 is 2 x 3 x 3 = 18.

The prime factorization of 27 is 3 x 3 x 3 = 27.

The occurrences of common prime factors of 18 and 27 are 3 and 3.

So the greatest common factor of 18 and 27 is 3 x 3 = 9.

Example: Find the GCF (20, 50, 120)

The prime factorization of 20 is 2 x 2 x 5 = 20.

The prime factorization of 50 is 2 x 5 x 5 = 50.

The prime factorization of 120 is 2 x 2 x 2 x 3 x 5 = 120.The occurrences of common prime factors of 20, 50 and 120 are 2 and 5.

So the greatest common factor of 20, 50 and 120 is 2 x 5 = 10.

Answer:

A

Step-by-step explanation:

Let's set hours as h.

We know that she earns 5 dollars an hour. If, for example, she worked 2 hours, she would have earned 2*5=10 dollars. This is 5h.

Next, we know that she got 186 dollars in tips. Tips means that she earned extra money, so therefore, the equation is 5h+186, or A