MATHEMATICS MIDDLE SCHOOL



Factor completely 2x3 + x2 - 18x – 9.

Answers

Answer 1
Answer: 2x^3+x^2-18x-9=x^2(2x+1)-9(2x+1)\n\n=(2x+1)(x^2-9)=(2x+1)(x^2-3^2)\n\n=(2x+1)(x-3)(x+3)
Answer 2
Answer:

The completelyfactoredform of 2x³ + x² - 18x - 9 is (2x + 1)(x - 3)(x + 3).

We have,

To factor completely the expression 2x³ + x² - 18x - 9, we can follow these steps:

- Step 1: Group the terms in pairs:

(2x³ + x²) + (-18x - 9)

- Step 2: Factor out the greatest commonfactor from each pair:

x²(2x + 1) - 9(2x + 1)

- Step 3: Observe that we have a common binomial factor of (2x + 1).

Factor it out:

(2x + 1)(x² - 9)

- Step 4: The binomial (x² - 9) is a difference of squares and can be further factored as:

(2x + 1)(x - 3)(x + 3)

Therefore,

The completelyfactoredform of 2x³ + x² - 18x - 9 is (2x + 1)(x - 3)(x + 3).

Learn more about expressions here:

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Answers

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Answers

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