MATHEMATICS HIGH SCHOOL

a boat takes 4 hours to go 20 miles upstream.It can go 32 miles downstream in same time.Find the rate of the current and the rate of the boat in still water.

Answers

Answer 1

Answer:

Let

x---------> the rate of the boat in still water in mph

y--------> the rate of the current in mph

we know that

Upstream

$rate=(20)/(4) \n\n rate=5mph$

$x-y=5$ equation $1$

Downstream

$rate=(32)/(4) \n\n rate=8mph$

$x+y=8$ equation $2$

Adds equation $1$ and equation $2$

$x-y=5\n x+y=8\n -----\n 2x=13\n x=6.5mph$

Find the value of y

$x+y=8\n y=8-x\n y=8-6.5\n y=1.5 mph$

therefore

the answer is

the rate of the boat in still water is $6.5 mph$

the rate of the current is $1.5 mph$

Answer 2

Answer: Upstream: It goes about 5 mph b/c 20 miles/4 hours= 5 mphDownstream:It goes about 8 mph b/c 32 miles/ 4 hours=8 mphHope I helped! :-)

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lalo has 1500 minutes per month on his cell phone plan. how many more minutes can he use if he has already talked for 785 minutes?

Answers

Answer:

Lalo can talk for 715 minutes more in that month if he has already talked for 785 minutes.

Step-by-step explanation:

Total number of minutes per month lalo has on his cell phone plan = 1500

Number of minutes he has already talked in that month = 785

Number of minutes available to talk = total number of minutes he has - total number of minutes he has already used.

= 1500 - 785

= 715 minutes.

Thus, Lalo can talk for 715 minutes more in that month if he has already talked for 785 minutes.

All you have to do is subtract 1500-785 in order to find the number of minutes left for him.
1500-785=715 more minutes left

Simplify this expression: 19 – (–8) – (–14) = ?
A. –7
B. –3
C. 41
D. 25

Answers

The answer is C. 41.

A lizard needs to stay a safe distance from a cactus. The diameter of the cactus is 12 inches. If the lizard is 8 inches from a point of tangency, find the direct distance between the lizard and the cactus (x). If necessary, round to the hundredths place.