What will a graph that represent the inverse of h(x)=-3x+6 look like?

Answers

Answer 1

Answer: $h(x)=-3x+6\n\nfor\ x=0\to y=-3\cdot0+6=6\to(0;\ 6)\n\nfor\ x=2\to y=-3\cdot0+6=-6+6=0\to(2;\ 0)\n\nh^(-1)(x):\n\ny=-3x+6\n3x=-y+6\ \ \ \ /:3\nx=-(1)/(3)y+2\n\nh^(-1)(x)=-(1)/(3)x+2$

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To solve the equation below by completing the square what is the first step? 4x^2+16x=20

A. add 8 to each side of the equation.
B. add 64 to each side of the equation.
C. multiply both sides of the equation by 1/4.
D. multiply both sides of the equation by 1/8.

Answers

C multiply both sides of the eaqaution by 1/4

8x-2(x+1)=2(3x-1)A.0
B.2
C.no solution <-- that's what I think it is.
D.identity.

Can someone check my answer

Answers

$8x-2(x+1)=2(3x-1)\n\n8x-2x-2=6x-2\n\n6x-6x=-2+2\n\n0=0\n\nD.\ identity$

Can anyone help me? The directions are:Choose the correct conic section to fit each equation. Is it a Circle, Ellipse, Parabola, or Hyperbola?
1) x^2 + y^2 = 16

Answers

$Genereal\ formula\ for\ circle:\n(x-a)^2+(y-b)2=r^2\nCenter\ of\ circle:\ S(a,b)\nr-radius\n\nx^2+y^2=4^2\nIt's\ equation\ of\ circle,\ which\ has\ S(0,0)\ and\ radius\ 4.$

Find two consecutive number which add up to 89.
What are the steps.

Answers

let the first number be x
the second number is (x + 1)
according to the condition,
x+(x+1)=89
or, 2x+1=89
or, 2x=89-1
or, 2x=88
or, x=88/2
or, x = 44

therefore,
first number = 44
second number = 45

irst lets represent
x as first number and x+1 as ne t consecutive number

x+x+1=89
2x=88
x=44

therefore the consecutive numbers are 44 and 45

Add one term to the polynomial expression 14x^19 - 9x^15 + 11x^4 + 5x^2 + 3 to make it into a 22nd degree polynomial

Answers

The required polynomial to a 22nd degree is $P(x)=x^(22)+14x^(19) - 9x^(15) + 11x^4 + 5x^2$

Given the polynomial function, $14x^(19) - 9x^(15) + 11x^4 + 5x^2$ ,, we are to add one term to the polynomial to make it into a 22nd-degree polynomial.

Note the highest and leading power of the variable of any function is the degree of such function.

To convert the given polynomial to a 22nd-degree function, we will simply add a variable term x with a degree of 22 to have:

$P(x)=x^(22)+14x^(19) - 9x^(15) + 11x^4 + 5x^2$

Hence the required polynomial to a 22nd degree is $P(x)=x^(22)+14x^(19) - 9x^(15) + 11x^4 + 5x^2$

Learn more here: brainly.com/question/2706981

Given:

The polynomial is

$14x^(19)-9x^(15)+11x^4+5x^2+3$

To find:

One term which is used to add in given polynomial to make it into a 22nd degree polynomial.

Solution:

Degree of a polynomial is the highest power of the variable.

Let,

$P(x)=14x^(19)-9x^(15)+11x^4+5x^2+3$

Here, the highest power of x is 19, so degree of polynomial is 19.

To make it into a 22nd degree polynomial, we need to need a term having 22 as power of x.

We can add $kx^(22)$ , where k is constant.

So add $x^(22)$ in the given polynomial.

$P(x)=x^22+14x^(19)-9x^(15)+11x^4+5x^2+3$

Now, the degree of polynomial is 22.

Therefore, the required term is $x^(22)$ .

Put the following equation of a line into slope-intercept form, simplifying all fractions2x+4y=4

Answers

Answer:

y = -1/2x + 1

Step-by-step explanation:

You want to get y by itself. subtract 2x from both sides. now you're left with 4y = -2x + 4. then divide both sides by 4 to get y by itself. this equals y = -1/2x + 1

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