If x + y = 9, z + y = 12, and z + x = 11, what is the average (arithmetic mean) of x, y and z?

Answers

Answer 1

Answer: $x+y=9 \n z + y = 12 \n z + x = 11 \n x+y+ z + y+ z + x=9+12+11 \n 2x+2y+ 2z=32 \n x+y+ z=16$

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State whether true or false 12+(-15) =12-15

Solve by substitution
y=x+3
y=2x+5

Answers

y = x+3
y = 2x+5
x+3 = 2x+5
x+8 = 2x
x = 8

I think I did that right, anyway.

y=x+3
y=2x+5

1. Solve for the variable that is easiest to find.
In this case I will solve for x.
y=x+3
-3 -3
y-3=x

2. Now plug in (y-3) for x in the other equation.
y=2(y-3)+5 ~use distributive property
y=2y-6+5 ~combine like terms
y=2y-1
-2y=-2y
-y=-1 ~multiply both sides by -1
y=1

3. Since you have a value for y you can plug it in to solve for x.
y=x+3
1=x+3
-3 -3
-2=x

Answers:
y=1
x=-2

Write (5+2yi)(4-3i)-(5-2yi)(4-3i) on a+bi form, where y is a real number

Answers

the answer is attached here

What is the solution of the equation? 16 = –d + 6a. 10
b. –10
c. –9
d. –15

Answers

If you would like to know what is the solution of the equation 16 = - d + 6, you can calculate this using the following steps:

16 = - d + 6
16 - 6 = - d
10 = - d
d = - 10

The correct result would be b. - 10.

16 = -d + 6

Subtract 6 on both sides

16 - 6 = -d + 6 - 6

10 = -d

Divide both sides by -1

10/-1 = -d/-1

d = - 10

Your answer is B. -10.

What element in the excerpt from Life on the Mississippi most suggests that it is a realist text?A.It has dialogue that is both witty and believable.
B.It contains well-rounded and diverse characters.
C.It concerns itself with the trials of a daily occupation.
D.It pays close attention to the physical details of a setting.

Answers

C.It concerns itself with the trials of a daily occupation.

Answer:

Step-by-step explanation:

c................

Find the volume of the square based pyramid.

Answers

A = 1/3 * s^2 * h where s is a side of the base and h is the height.

Finding the height of the pyramid:

$\left((6)/(2) \right )^(\!\!2)+h^(2)=8^(2)\n \n \n 3^(2)+h^(2)=8^(2)\n \n h^(2)=8^(2)-3^(2)\n \n h^(2)=64-9\n \n h^(2)=55\n \n h=√(55)\mathrm{~m}$

Finding the base area:

$S=6^(2)\n \n S=36\mathrm{~m^(2)}$

Formula for the volume of the pyramid:

$V=(S\cdot h)/(3)\n \n \n V=(36\cdot √(55))/(3)\n \n \n V=(\diagup\!\!\!\! 3\cdot 12\cdot √(55))/(\diagup\!\!\!\! 3)\n \n \n \boxed{\begin{array}{c} V=12√(55)\mathrm{~m^(3)} \end{array}}$

Which is the solution to the following equation?
4x^2-12x+9=5

Answers

we assume that
if xy=0
x and y=0

first make it equal to zero

minus 5 on both sides
4x^2-12x+4=0
undistribute 4 for ease
4(x^2-3x+1)=0
since 4 does not equal zero, and the only thing that will get it to zero is 0,
x^2-3x+1=0
use quadratic equation

if you hahve
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^(2)-4ac} }{2a}$
1x^2-3x+1=0
a=1
b=-3
c=1

x= $\frac{-(-3)+/- \sqrt{(-3)^(2)-4(1)(1)} }{2(1)}$
x= $(3+/- √(9-4) )/(2)$
x= $(3+/- √(5) )/(2)$
x= $(3+ √(5) )/(2)$ or $(3- √(5) )/(2)$

aprox
x=2.61803 or 0.381966

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