Answer:
The number of times faster Abigail is on her skateboard than she is walking is 4 times
Step-by-step explanation:
The information given are;
Abigail was skateboarding home (let the distance home = D)
The distance Abigail had traveled when her skateboard broke = 2/3 of D
The distance of the rest (remaining) of the way home = 1 - 2/3 of D = 1/3 of D
The time Abigail took in walking the rest of the way home = 2 × t, Time it will take on the skateboard
Given that t is the time it takes Abigail to arrive home on skateboard alone, we have;
Speed on skate board, S = Distance/Time = D/t
Therefore, the time it took Abigail to travel two thirds (2/3) of D is given as follows;
The total time it took Abigail to get to her home = Time of walking + Time on skateboard
The question also states that he total time it took Abigail to get to her home by walking and skateboarding because her skateboard broke = 2×t
Therefore, the total time it took Abigail to get to her home = 2×t = Time of walking + Time on skateboard = Time of walking +
Which gives;
2×t = Time of walking +
Time of walking = =
∴ The time Abigail walked 1/3·D =
Abigail walking speed is then
To compare how many times faster is Abigail on her skateboard than she is walking, we divide the expression (formula) for the speed of skateboarding with the (formula) for the speed of walking as follows;
The number of times faster is 4 that is Abigail is four times faster on her skateboard than she is walking.
Answer:
340
Step-by-step explanation: 200 * .14 = 28 then 28*5= 140 then 140+200=340
Answer:
340 in 5 years
Step-by-step explanation:
I set it up as a fraction so I could find 14% of 200.
14/100 = x/200
Then I cross multiplied
100x = 2800
Simplify
x=28
Twenty-eight is 14% of 200. Multiply 28 by 5.
28 x 5 = 140
Add 140 to 200
340
Step-by-step explanation:
x-(-11)
= x+11
= 14+11
= 25
Answer:
.400
Step-by-step explanation:
88 inches is only divede and math