Answer:
~91 chirps/min
Step-by-step explanation:
This exercise is asking us to estimate based on the values in the table. If we know the temperature is 65°F, let's find the closest values given to interpolate (assuming the data is fairly linear, which it appears to be).
Looks like the closest ones are 60° and 68°. We will look at their corresponding chirps/min and guess a number in between those two.
60° -> 81 chirps/min
68° -> 97 chirps/min
Because 65 is closer to 68 than 60, we expect our result to be closer to 97 than 81.
slope = rise/run
= = 2 chirps/min/°F. So for every °F increase, we expect to increase by 2 chirps/min.
60+5 = 65, so let's add 2*5 = 10 chirps/min to 60 to get 91 chirps/min. This corresponds with what we would have guessed.
x - 9 = 17,
x + 12 = 20,
2x = 16.
the temperature in Austria will be 10 degrees Celsius at half past 11.
We can start by calculating how much the temperature will increase from 8 am to 12 pm:
From 8 am to 9 am: temperature increases by 2 degrees Celsius
From 9 am to 10 am: temperature increases by 2 degrees Celsius
From 10 am to 11 am: temperature increases by 2 degrees Celsius
From 11 am to 12 pm: temperature increases by 2 degrees Celsius
Therefore, the temperature at 12 pm will be:
-5 + 2 + 2 + 2 + 2 = -5 + 8 = 3 degrees Celsius
Now, we need to calculate how much the temperature will increase from 12 pm to 11:30 am:
From 12 pm to 1 pm: temperature increases by 2 degrees Celsius
From 1 pm to 2 pm: temperature increases by 2 degrees Celsius
From 2 pm to 3 pm: temperature increases by 2 degrees Celsius
From 9 pm to 10 pm: temperature increases by 2 degrees Celsius
From 10 pm to 11 pm: temperature increases by 2 degrees Celsius
From 11 pm to 11:30 pm: temperature increases by 1 degree Celsius
Therefore, the temperature at half past 11 will be:
3 + 2 + 2 + 2 + 1 = 10 degrees Celsius
learn more about temperature here:
#SPJ4