Can someone help with geometry !! If m

Answers

Answer 1
Answer: i can try to help you if you type the rest of your question!

Related Questions

Quadrilateral ABCD has vertices A(6,-3), B(8,-1), C(3,-1), and D(1,-3). Quadrilateral WXYZ has vertices W(1,6), X(2,7), Y(-1,7), and Z(-2,6). Which is true regarding the two shapes?
Find all real zeros of the function. f(x)=4(x^2-1)(x-3)(x+3)^2
Heather sampled the ages of 50 randomly selected people that frequented a store and obtained a mean of 24. She constructed a 95% confidence interval which was (19.1, 28.9). What is the margin of error?A) 2.5 years B) 4.9 years C) 5 years D) 6.7 years
Mohamed bought 1.8 pounds of green bean. The green bean cost 1.27 dollars per pound. what was the total cost Mohammed green beans?
What is the range of the data set?0|1 4 4 1|1 2 7 2|0 3|5 5 4|8 Key: 3|5 means 35

Let y be a function of x such that 2x-3y=6. What is the rate if change of y with respect to x?

Answers

2x - 3y = 6
first, isolate y:
-3y = -2x + 6
y = (2/3)x - 2
This is a linear function in standard form, so we know that the slope (in this case the rate of change of y in respect to x) is 2/3

Please someone help me with this, it’s due today

Answers

Answer:

~91 chirps/min

Step-by-step explanation:

This exercise is asking us to estimate based on the values in the table. If we know the temperature is 65°F, let's find the closest values given to interpolate (assuming the data is fairly linear, which it appears to be).

Looks like the closest ones are 60° and 68°. We will look at their corresponding chirps/min and guess a number in between those two.

60° -> 81 chirps/min

68° -> 97 chirps/min

Because 65 is closer to 68 than 60, we expect our result to be closer to 97 than 81.

slope = rise/run

(97-81)/(68-60) = (16)/(8) = 2 chirps/min/°F. So for every °F increase, we expect to increase by 2 chirps/min.

60+5 = 65, so let's add 2*5 = 10 chirps/min to 60 to get 91 chirps/min. This corresponds with what we would have guessed.

How can 11,14,13 and 19 equal to 4

Answers

19 - 13 = 6
6 + 11 = 17
17 - 13 = 4

Thirty times the square of a non-zero number is equal to eight times the number. what is the number?

Answers

You said that        30 x²  =  8 x

I can divide
each side by 'x':     30 x = 8
 
Then divide
each side by 30:        x  =  8 / 30  =  4/15 .

Check to see if it works:

Does    30 (4/15)²  =  8 (4/15)  ?

Well, (4/15)² = 16/225

       30 · 16/225 = 480/225  =  32/15
and
         8 · 4/15  =  32/15                    yay !
Hello,

let x the unknowed number,

30*x²=8*x
==> 30x=8 (for x ≠0)
==>x=8/30
==>x=4/15

Confusion dans la traduction mentale désolé.

Which equation does not have the same solution as the others?x/4 = 2,
x - 9 = 17,
x + 12 = 20,
2x = 16.

Answers

If you would like to know which equation doesn't have the same solution as the others, you can calculate this using the following steps:

x/4 = 2 ... x = 4 * 2 = 8

x - 9 = 17 ... x = 17 + 9 = 26

x + 12 = 20 ... x = 20 - 12 = 8

2 * x = 16 ... x = 16/2 = 8

The correct result would be x - 9 = 17.
(x)/(4)=2\nMultiply\ by\ 4\ on\ both\ sides.\nx=2*4\n{\boxed{x=8}


\n\nx-9=17\nAdd\ 9\ on\ both\ sides.\nx=17+9\n{\boxed{x=26}

x+12=20\nSubtract\ 12\ on\ both\ sides.\nx=20-12\n{\boxed{x=8}

2x=16\nDivide\ by\ 2\ on\ both\ sides.\nx=(16)/(2)\n{\boxed{x=8}


\sf\ The\ only\ equation\ that\ did\ not\ have\ the\ same\ solution\ as\ the\nothers\ was\n {\boxed{x-9=17}

The temperature in austria one morning was -5 degrees celcias at 08 oclock and increased by 2 degrees celcias every hour until 12 oclock ,what will be the temperature be at half past 11

Answers

the temperature in Austria will be 10 degrees Celsius at half past 11.

We can start by calculating how much the temperature will increase from 8 am to 12 pm:

From 8 am to 9 am: temperature increases by 2 degrees Celsius

From 9 am to 10 am: temperature increases by 2 degrees Celsius

From 10 am to 11 am: temperature increases by 2 degrees Celsius

From 11 am to 12 pm: temperature increases by 2 degrees Celsius

Therefore, the temperature at 12 pm will be:

-5 + 2 + 2 + 2 + 2 = -5 + 8 = 3 degrees Celsius

Now, we need to calculate how much the temperature will increase from 12 pm to 11:30 am:

From 12 pm to 1 pm: temperature increases by 2 degrees Celsius

From 1 pm to 2 pm: temperature increases by 2 degrees Celsius

From 2 pm to 3 pm: temperature increases by 2 degrees Celsius

From 9 pm to 10 pm: temperature increases by 2 degrees Celsius

From 10 pm to 11 pm: temperature increases by 2 degrees Celsius

From 11 pm to 11:30 pm: temperature increases by 1 degree Celsius

Therefore, the temperature at half past 11 will be:

3 + 2 + 2 + 2 + 1 = 10 degrees Celsius

learn more about temperature here:

brainly.com/question/30831220

#SPJ4