Answer with explanation:
A set of numbers that is triplet is said to form the sides of a right triangle, if it satisfies Pythagorean Theorem,which states that
Square of longest side is equal to sum of Squares of other two sides.
1.First triplet=4,4,4
As, 4²≠4²+4²
Hence it does not form Pythagorean triplet.
2. Second triplet=4, 6.93, 8
Largest side length =8
8²=64
Sum of squares of two smaller sides =(6.93)²+4²
=48.0249+16
=64.0249
=64
3. Third triplet=11.2, 16.2, 19.2
Largest side length =19.2
(19.2)²=368.64
Sum of squares of two smaller sides =(11.2)²+(16.2)²
=125.44+262.44
=387.88
=388(approx)
Option B ⇒4,6.93, 8
{(–5, 1), (–5, 0), (–2, 1), (–1, 4), (6, 2)}
B.
{(–5, 1), (–2, 0), (–2, 2), (3, 4), (6, 2)}
C.
{(–5, 1), (–2, 0), (–1, 1), (2, 4), (6, 3)}
D.
{(–5, 3), (–2, 0), (–1, 2), (6, 4), (6, 3)}