The first one is X,Y= 5
Number 2 Is x= 10 and y= 4
Using the binomial distribution, it is found that there is a 0.0369 = 3.69% probability that 3 or more were involved in an accident last year.
For each driver, there are only two possible outcomes, either they were involved in an accident, or they were not. The probability of a driver being involved in an accident is independent of any other driver, hence, the binomial distribution is used to solve this question.
Binomial probability distribution
The parameters are:
In this problem:
The probability is:
In which:
Then
0.0369 = 3.69% probability that 3 or more were involved in an accident last year.
To learn more about the binomial distribution, you can check brainly.com/question/24863377
Answer:
Therefore the probability that 3 or more were involved in an accident last year is 0.376.
Step-by-step explanation:
Binomial distribution:
A discrete random variable X having the set {0,1,2.....,n} as the spectrum, is said to have binomial distribution with parameter n= the number of trial and p = probability of getting successes in one trial if the p.m.f of X is give by
for x=0,1,2,....,n
=0 elsewhere
where , n is a positive integer and 0<p<1.
Given that,
7% of all drivers were involved in an accident last year that was determined by a car insurance company.
p= 7%=0.07, n=11, x=3
P(X≥3)
= 1-P(X≤2)
= 1- P(X=0)-P(X=1)-P(X=2)
=1-0.624
≈0.376
Therefore the probability that 3 or more were involved in an accident last year is 0.376.
3
4
5
6
9
10
The number 84 is divisible by 2,3,4 and 6.
One of the four fundamental arithmetic operations, or how numbers are combined to create new numbers, is division.
The numbers which divide 84 completely are:-
2 ⇒ 84 ÷ 2=24
3 ⇒ 84 ÷ 3=28
4 ⇒ 84 ÷ 4=21
6 ⇒ 84 ÷ 6=13
Hence, the numbers are 2,3,4 and 6.
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A.T
B.
There is no relationship between the variables.
C.H
Answer:
3.5 miles
Step-by-step explanation:
From the question, we have the following information:
The super speedway at Daytona International Speedway is = 2.5 miles
long
The road course there is = 1.4 times as long as the super speedway.
How long is the road course?
The length of the road course is calculated as:
1.4 × length of the super speedway
1.4 × 2.5 miles
=>3.5 miles
Therefore, length of the road course I s 3.5 miles.