A tank with a flat bottom is filled with water to a height of 4 meters. What is the pressure at any point at the bottom of the tank? (You can ignore atmospheric pressure when calculating your answer.)A. 18.9 kPa
B. 9.8 kPa
C.39.2 kPa
D. 4.0 kPa

Answers

Answer 1
Answer:

Answer

C.39.2 kPa


Explanation

The pressure in liquids depend on the depth or what we call the liquid column(h), the density of the liquid(σ) and the the acceleration due to gravity(g).

h = 4.00 m

σ = 1000 Kg/m³

g = 9.8m/s²


Pressure Is given by;

P = σgh

= 1000 × 9.8 × 4

= 39200 Pa

=39.2 KPa

Answer 2
Answer: P=pgh, remeber that g=9.8 , so ignoring the atmosheric pressure youwould just multiply 9.8x4 and you would get 39.2KPa

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3. You are walking in Paris alongside the Eiffel Tower and suddenly a croissant smacks you on the head and knocks you to the ground. From your handy dandy tourist guidebook you find that the height of the Eiffel Tower is 300.5 m. If you neglect air resistance, calculate how many seconds the croissant dropped before it tagged you on the head.

Answers


As absurd as the concept is, we must assume that a croissant
can fall 300.5 meters through the moisture-laden, perfumed and
polluted Parisian air with no air resistance whatsoever.

Acceleration due to gravity on Earth:  9.8 m/s²

Distance in clean,
unimpeded free-fall         = (1/2) (acceleration) x (time²) 

                                            300.5 m  =  (1/2)  (9.8 m/s²) (T²)
Divide each side
by (4.9 m/s²):                  (300.5 m) / (4.9 m/s²)  =  T²

Take the square root
of each side:                     T = √(300.5/4.9) (s²)

                                                               =  7.831 seconds .

What are the fundamental units involved in a unit of the given derived quantitiesDensity
Acceleration
Force
Pressure
Work​

Answers

Answer:

Density → Mass and Length.

Acceleration → Length and Time.

Force → Mass, Length and Time.

Pressure → Mass, Length and Time.

Work → Mass, Length and Time.

A car moving with a velocity of 20 meters/second has1.8 * 105 joules of kinetic energy. What is the mass of the car?

Answers

Kinetic energy is the product of mass and the square of the velocity of the moving object. In this case, we substitute the given data, that is 1.8 x10^5 joules = m * (20 m/s2)^2. Extracting the mass, the mass of the car therefore is equal to 450 kg

Explanation :

Given that,

Velocity of the car, v = 20 m/s

Kinetic energy of the car, E_k=1.8* 10^5\ J

Kinetic energy is given by :

E_k=(1)/(2)mv^2

m=(2E_k)/(v^2)

So, m=(2* 1.8* 10^5\ J )/((20\ m/s)^2)

m = 900 kg

Hence, the mass of the car is 900 kg

Two objects are moving at equal speed along a level, frictionless surface. the second object has twice the mass of the first object. they both slide up the same frictionless incline plane. which object rises to a greater height?

Answers

Answer:

They both rises to same height.

Explanation:

When an object is sliding up in friction less surface than according to conservation of energy its potential energy will be converted into kinetic energy.

mgH=(1)/(2)mv^(2)\n v=√(2gH)

Here, m is the mass, v is the velocity, g is the acceleration due to gravity and H is the height.

Here the height is independent on the mass of an object and its only depend on velocity.

Now according to the question, two objects have same velocity but they have different masses.

Therefore, they rises to the same height because  height will not change with mass.

Both objects rise to the same height

\texttt{ }

Further explanation

Let's recall Kinetic Energy Formula as follows:

\large {\boxed{Ek = (1)/(2)mv^2} }

Ek = Kinetic Energy ( Joule )

m = mass of the object ( kg )

v = speed of the object ( m/s )

Let us now tackle the problem !

\texttt{ }

Given:

initial speed of first object = initial speed of second object = v

final speed of first object = final speed of second object = 0

mass of first object = m

mass of second object = 2m

Asked:

height = H = ?

Solution:

We will use Conservation of Energy to solve this problem:

Ep_1 + Ek_1 = Ep_2 + Ek_2

0 + (1)/(2)mv^2 = mgH + 0

(1)/(2)v^2 = gH

v^2 = 2gH

\boxed {H = (v^2)/(2g)}

\texttt{ }

H_1 : H_2 = (v_1^2)/(2g) : (v_2^2)/(2g)

H_1 : H_2 = v_1^2 : v_2^2

H_1 : H_2 = v^2 : v^2

H_1 : H_2 = 1 : 1

\boxed{ H_1 = H_2 }

\texttt{ }

Conclusion:

Both objects rise to the same height

\texttt{ }

Learn more

\texttt{ }

Answer details

Grade: High School

Subject: Physics

Chapter: Energy

What component of Star Wars is possible

Answers

Comparing to current technology, here are some component of star wars that is  possible :

- The drones
Remember the flying drones that could shoot stuff in star wars ? we already made that

- Prosthetic limb
Luke's bionic hand in star wars ? we also already made that

- The probe droids
We used a similar thing when our scientist done an expedition to the moon

Answer:

Droids. AI is under development right now.

Space ships. WE have some spaceships, but not like that.

Rebellion

Empire

etc.

Explanation:

A disk made of many small particles of Rock and ice in orbit around a planet is called

Answers

The correct answer is ring. A disk made of many small particles of rock and ice in orbit around a planet is called ring. The rings of the planet Saturn is considered to be the most extensive planetary rings system in the Solar System.