Jonathan’s class has 30 boys. Of the students in his class, 60% are girls. How many girls are in Jonathan’s class?

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Answer 1
Answer: Having that 30 boys is 40% of students.30 is 40% of students the how many students is 100%. Naming X number total of students.X=(30*100)/40=75. Then having that there are 30 boys, numbers of girls is 75-30=45.

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3x + y = 17
4x - y = 18

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The two equations given are
3x + y = 17 and 4x - y = 18
Now we will first take one equation
3x + y = 17
Then
y = 17 - 3x
Now replacing the value of y in the second equation we get
4x - y = 18
4x - (17 - 3x) = 18
4x + 3x - 17 = 18
7x = 35
 x = 35/7
   = 5
Putting the value of x in the first equation we get
3x + y = 17
(3 * 5) + y = 17
15 + y = 17
y = 17 - 15
y = 2
So the value of x is 5 and y is 2
3x+y=17
subtract 3x on both sides
y=17-3x
substitute 17-3x for y in the second equation
4x-(17-3x)=18
7x-17=18
7x=35
x=5

and now that you know x=5 you can plug that in to either of the original equations
3(5)+y=17
15+y=17
subtract 15 from both sides
y=2

Suppose that c (x )equals 7 x cubed minus 70 x squared plus 13 comma 000 x is the cost of manufacturing x items. Find a production level that will minimize the average cost of making x items.

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Answer:

A production level that will minimize the average cost of making x items is x=5.

Step-by-step explanation:

Given that

c(x)=7x^3-70x^2+13,000x

is the cost of manufacturing x items

To find a production level that will minimize the average cost of making x items:

The average cost per item is f(x)=(c(x))/(x)

Now  we get f(x)= 7x^2-70x+13000

f(x) is continuously differentiable for all x

Here x≥0 since it represents the number of items.,

Put x=0 in 7x^2-70x+13000

For x=0 the average cost becomes 13000

f(0)=7(0)^2-70(0)+13000

=13000

∴ f(0)=13000

To find Local extrema :

Differentiating f(x) with respect to x

f^(\prime) (x)=14x-70=0

14x=70

x=(70)/(14)

∴  x=5 gives the minimum average cost .

At x=5 the average cost is

f(5)=7(5)^2-70(5)+13000

=12825

∴ f(5)=12825 which is smaller than for x=0 is 13000

∴ f(x) is decreasing between 0 and 5 and it is increasing after 5.

Answer:

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Step-by-step explanation:

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Find (f - g)(x) if f(x) = x2 ­- x - 6 and g(x) = 2x2 - 3x + 4a. -x2 + 2x - 10
b. x2 - 4x - 2
c. 3x2 - 4x - 2
d. x2 + 2x - 10

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