George walks 1 mile to school. He leaves home at the same time each day, walks at a steady speed of 3 miles per hour, and arrives just as school begins. Today he was distracted by the pleasant weather and walked the first 12 mile at a speed of only 2 miles per hour. At how many miles per hour must George run the last 12 mile in order to arrive just as school begins today? 4

Answers

Answer 1

Answer: i'll just assume you meant he has to walk 24 miles to school since 12 + 12 isn't 1. if he normally walks 3 miles an hour for 24 miles, his average speed is also 3 miles an hour. if he walks 2 miles an hour for the first half of his 24 mile journey, he has to walk 4 miles an hour for the second part, since he has to reach his average speed of 3 miles an hour

Answer 2

Answer:

Final answer:

George must run the last 1/2 mile at a speed of 2/3 mile per hour to arrive just as school begins today.

Explanation:

To find the speed George must run the last 1/2 mile in order to arrive just as school begins today, we can start by calculating the time it took for George to walk the first 1/2 mile at a speed of 2 miles per hour. We can use the formula Time = Distance / Speed to calculate the time: Time = (1/2) mile / 2 miles per hour = 1/4 hour = 15 minutes.

We know that George arrives just as school begins, so the total time it takes for him to walk 1 mile is the same as the total time it takes for him to walk the first 1/2 mile at 2 miles per hour, plus the time it takes for him to run the last 1/2 mile at a new speed. Therefore, the total time is 15 minutes + time to run the last 1/2 mile. We can set up the equation: (15 minutes) + (1/2 mile / speed) = 60 minutes (as 60 minutes is one hour). We can then solve for the speed by subtracting 15 minutes from both sides and rearranging the equation:

1/2 mile / speed = 45 minutes = 3/4 hour. Multiplying both sides of the equation by the speed:

(1/2 mile) = (3/4 hour) * speed

speed = (1/2 mile) / (3/4 hour) = (1/2 mile) * (4/3 hour) = (1/2)(4/3) = 2/3 mile per hour.

Learn more about Calculating speed here:

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Solve the equation for y. 6y-1.5x=8

Answers

Answer:

Value of y is:

y = 0.25x + 1.33

Step-by-step explanation:

We are given a equation:

6y-1.5x=8

and we have to solve for y

6y-1.5x=8

⇒ 6y = 1.5x + 8

On dividing both sides by 6, we get

y = 0.25x + 1.33

Hence, On solving the equation for y, we get

y = 0.25x + 1.33

Solve for y by simplifying both sides of the equation, then isolating the variable. So your answer would be y=0.25x+4/3

Kevin is playing a game at the state fair. For each ball he can toss into a jar, he gets -2 points. To win a stuffed animal, he must earn a score of -24 or less. How many times does he have to toss a ball into a jar?

Answers

To solve this, find the number of balls (b) times -2 to equal -24 or less. b×-2(less than it equal to sign)-24. Solve for b.

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Suppose P(A) = 0.9, P(B) = 0.3, and P(B|A) = 0.2. What is P(A|B) ?

Answers

By definition of conditional probability,

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Similarly,

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Answers

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it is d price the coffee maker was sold + the discount price
50 dollars + 20 dollars = 70 dollars

A golfer hits a ball from a starting elevation of 5 feet with a velocity of 70 feet per seconddown to a green with an elevation of -4 feet. The number of seconds t it takes the ball to
hit the green can be represented by the equation - 16t2 + 706 + 5 = -4. How long does it
take the ball to land on the green?
It takes the ball |
seconds to land on the green.

Answers

Answer:

Time, t = 4.5 s

Step-by-step explanation:

The number of seconds t it takes the ball to hit the green can be represented by the equation :

$-16t^2 + 70t + 5 = -4$

It means that the initial velocity is 70 ft/s. The above equation becomes:

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It is required to find the time taken by the ball to land on the ground. It is a quadratic equation. The solution of quadratic equation is given by :

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t = −0.125 and t = 4.5 s

Time cannot be negative. So, the time taken by the ball to land on the ground is 4.5 seconds.

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Answers

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