The Al-Aqsa Mosque and Dome of the Rock are located in
Answers
The correct answer is - Jerusalem
Related Questions
How does heat differ from temperature
Look closely at the valence electrons in all eight columns of your table from part C. Which element's location does notmatch the pattern shown in the table?o helium (He)o hydrogen (H)sodium (Na)O argon (Ar)
The process of chemical cycling is known as a biogeochemical cycle. Why was it called biogeochemical cycle? A. absorbs the chemical involved from the sediment. B. takes place over a long period of time. C. involves both living and nonliving components. D. withdraws the chemical from the atmosphere as a gas.
In a very violent reaction called a thermite reaction, aluminum metal reacts with iron (III) oxide to form iron metal and aluminum oxide according to the following equation:
A. they remain level since densities in both plates are equal.
B. they both push back down into the mantle
C. one plate rides over the other one and forms a trench
D.they buckle upward and form mountains
Answers
Answer:
D. They buckle upward and form mountains.
Explanation:
When two plates (either oceanic or terrestrial) converge and they are of similar density then they will crash into each other and form mountains. A great example of this is when India crashed into the Asian continent and the Himalayas were formed.
Answers
Answer:
A.
Explanation:
The amount of mass always stays the same, matter cannot be created nor destroyed, it can only change forms. Thus, the answer is A.
In a chemical reaction the total mass of all the substances taking part in the reaction remains the same. Also, the number of atoms in a reaction remains the same. Mass cannot be created or destroyed in a chemical reaction.
I hope this helps..
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is it amino acids???????
Answers
2C8H18+25O2----> 16CO2+18H2O when balanced. 10/114.229 g/mol = .087543... mol, converting to moles by dividing by molar mass. The ratio is 25/2, using the integers in front of the molecules in the balanced equation. so you just multiply .087543... by the ratio. That's 1.09429, which you multiply by the molar mass of O2, 31.9988 g/mol. The answer is 35.02 g O2
35.2 grams of oxygen are required to react with 10.0 grams of octane
Complete combustion of Hydrocarbons with Oxygen will be obtained by CO₂ and H₂O compounds.
If O₂ is insufficient there will be incomplete combustion produced by CO and H and O
Hydrocarbon combustion reactions (specifically alkanes)
For gas combustion reaction which is a reaction of hydrocarbons with oxygen produces CO₂ and H₂O (water vapor). can use steps:
Balancing C atoms, H and last atoms O atoms
Octane combustion reaction
C₈H₁₈ + O₂ ---> CO₂ + H₂O
To equalize the reaction equation we give the reaction coefficients with variables a, b and c while the most complex compounds, namely Octane, we give the number 1
So the reaction becomes
C₈H₁₈ + aO₂ ---> bCO₂ + cH₂O
C atom on the left 8, right b, so b = 8
left H atom = 18, right 2c so 2c = 18 ---> c = 9
Atom O on the left 2a, right 2b + 2c, so 2a = 2b + 2c
2a = 2.8 + 9
2a = 16 + 9
2a = 25
a = 25/2
The equation becomes:
C₈H₁₈ + 25/2O₂ ---> 8CO₂ + 9H₂O or be
2C₈H₁₈ + 25O₂ ---> 16CO₂ + 18H₂O
To find the mass O2, we find the mole first from the mole ratio with Octane
- 1. We are looking for the octane mole
Mr. octane = 8.Ar C + 18.Ar H
Mr. octane = 8.12 + 18.1
Mr octane = 96 + 18
Mr octane = 114
known octane mass: 10 grams then the mole:
mol = gram / Mr
mol = 10/ 114
mol = 0.088
- 2. We look for the O₂ mole
because of the ratio of the reaction coefficient between O2 and octane = 25: 2 then the mole of O₂ =
25/2 x 0.088 = 1,1
So that the mass O₂ =
mole. Mr = 1.1 32
mass = 35.2 grams
a combustion reaction
the type of chemical reaction
The combustion of alkanes, alkenes, and alkynes
Complete combustion of a sample of a hydrocarbon
Keywords: Complete combustion of Hydrocarbons, alkanes, equalize the reaction equation
is an endothermic process. A 6.1589-g sample of the solid is placed in an evacuated 4.000-L vessel at exactly 24°C. After equilibrium has been established, the total pressure inside is 0.709 atm. Some solid NH4HS remains in the vessel.
(a) What is the KP for the reaction?
(b) What percentage of the solid has decomposed?
(c) If the volume of the vessel were doubled at constant temperature, what would happen to the amount of solid in the vessel?
Answers
Answer:
(a) Kp = 0.126
(b) 48.1 %
(c) More of the solid will decompose, therefore it will decrease.
Explanation:
(a) We have here the equilibrium decomposition of NH₄HS, according to the equation:
NH₄HS (s) ⇄ NH₃ (g) + H₂S
with an equlibrium cosnstant, Kp, given by
Kp = pNH₃ x pH₂S
where pNH3 and pH₂S are the partial pressures of NH₃ and H₂S .
Since 1 mol NH₃ is produced for every 1 mol H₂S, it follows that the partial pressure of NH₃ is equal to the partial pressure of H₂S ( from ideal gas law the pressure is proportional to number of mol):
pNH₃ = pH₂S = 1/2 (0.709) atm = 0.355 atm
and
Kp = 0.355 x 0.355 = (0.3545) ² = 0.126
(b) To solve this part we need to do a calculation based on the stoichiometry of the reaction by calculating the number of moles, n, a partial pressure of 0.355 atm represent.
From the ideal gas law we can calculate it:
PV = nRT ⇒ n = PV/RT
where P = 0.355 atm, V = 4.000 L, T = ( 24 + 273 ) K, and R is the gas constant 0.08205 Latm/Kmol.
n = 0.355 atm x 4.000 L / 0.08205 Latm/Kmol x 297
n = 0.058 mol
Now we can relate this 0.058 mol of NH₃ ( or H₂S ) to the number of moles of moles of NH₄HS that must have decompesed. Since it is a 1: 1 ratio:
(1 mol NH₄HS / 1 mol NH₃ ) x 0.058 mol NH₃ = 0.058 mol NH₄HS
Having the molar mass of NH₄HS, 51.11 g/mol we can calculate its mass:
0.058 mol NH₄HS x 51.11 g/mol = 2.9644 g
Percentage decomposition is then equal to:
2.9644 / 6.1589 g x 100 g = 48.1 %
(c) If the volume of the vessel, effectively we are reducing the pressure by a half , and the system will react according to LeChatelier's principle by producing more gaseous products to reach equilibrium again. Therefore, more of the solid NH₄HS will decompose, and the amount of it will we reduced compared to the previous part.
Which is larger a zinc atom or a zinc ion? explain