nolan divides his 88 toy cars into boxes to donate for a toy drive each box holds exactly 9 toy cars if only filled boxes can be shipped how many toy cars will not be shipped

Answers

Answer 1
Answer: 7 toy cars will not be shipped 

Answer 2
Answer: 9 x 9= 81
88 - 81=7
So 7 cars won't be shipped
Hope this helps :)

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Is 2 thirds equivalent to 6 tenths

Answers

You can't simplify 2/3, but you can divide both sides of 6/10 by 2 to simplify it. 6/10=3/5, which doesn't equal 2/3. 
2/3 is not equivalent to 6/10
thats because 3 times 3 doesnt equal to 10. it equals to 9.
so 2/3 equals to 6/9
hope it helped

Connor (is not or is) correct because the rate of water flowing is (greater than or less than or equal to) the slope. Water is flowing at a rate that is (greater than or equal to or less than) 2 gallon per minutes ​ HELP ME PLZZZZZZZZZZZZZZZ

Answers

Answer:

C

Connor is not correct because the rate of water flowing is equal to the slope. Water is flowing at a rate that is less than 2 gallon per minutes

Step-by-step explanation:

Part A

from the graph we can see (0, 0), (2, 1), (4, 2)

y=1/2x, slope is 1/2

option C

Part B

Connor is not correct because the rate of water flowing is equal to the slope. Water is flowing at a rate that is less than 2 gallon per minutes ​

Answer:

C

Step-by-step explanation:

Calculate the slope m using the slope formula

m = (y_(2)-y_(1)  )/(x_(2)-x_(1)  )

with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (4, 2) ← 2 points on the line

m = (2-0)/(4-0) = (2)/(4) = (1)/(2) → C

The slope indicates the rate of change.

Thus the water is flowing at (1)/(2) gallon per minute

Square root of 24x^6y^9​

Answers

Answer:

Step-by-step explanation:

Break the expression into individual pieces

24 can be written as (4)(6)

x^6 can be written as (x^3)^2

y^9 can be written as (y^4)^2(y)

Notice in the variables the focus on writing to the power of 2.

Square root and power of 2 are essentially inverse operations of each other, so they cancel each other out.

The square root of 4 is 2

The square root of (x^3)^2 is x^3

The square root of (y^4)^2 is y^4

The remaining 6 and y stay underneath the square root.

The final answer is then (2x^3y^4)(square root 6y)

Michael made a baby quilt that was 3 feet wide. It's perimeter was 16 feet. What was it's area?

Answers

in this situation you have to remember that this is going to be a rectangle so the with is going to be 3 and the opposite side will be the same size.
if one side is 3 the opposite side is also 3if you subtract their sum from the perimeter 16 it leaves 10 divided by 2 the other sides are 5.Area =bXh.3x5=15 which is the area

N^2+7n+15=5
show work please

Answers

n^2+7n+15=5
n^2 + 7n + 10 = 0
(n + 5)(n + 2) = 0
n + 5 = 0
n = -5
n + 2 = 0
n = -2

Answer: n = -5 and -2
n^2+7n+15=5

n^2+7n=-10

n^2+7n+((7)/(2))^2=-10+((7)/(2))^2

n^2+7n+(49)/(4)=-10+(49)/(4)

(n+(7)/(2))^2=(9)/(4)

n+(7)/(2)=\sqrt{(9)/(4)}

n=-(7)/(2)+\sqrt{(9)/(4)}

n=-2
n=-5

The coordinate plane below represents a city. Points A through F are schools in the city.graph of coordinate plane. Point A is at 2, negative 3. Point B is at negative 3, negative 4. Point C is at negative 4, 2. Point D is at 2, 4. Point E is at 3, 1. Point F is at negative 2, 3.

Part A: Using the graph above, create a system of inequalities that only contains points A and E in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above. (5 points)

Part B: Explain how to verify that the points A and E are solutions to the system of inequalities created in Part A. (3 points)

Part C: William can only attend a school in his designated zone. William's zone is defined by y < −x − 1. Explain how you can identify the schools that William is allowed to attend. (2 points)

Answers

Part A: You want two inequalities such that they overlap. So I'd draw two lines that slant downward at 45° below point C and another parallel line above point F. The shaded area should be between these to lines only. 
First, we choose the lines... 
y = -x + 2 has C and F above it and all other noted points below it. y = -x + 9 has all the points below it on the graph. 
So if we include all points above the first line and all points below the second line, we obtain our intersected shaded area. To do this changes our linear equations to linear inequalities. 
All points above y = -x + 2 would then be y > -x + 2 
All points below y = -x + 9 would then be y < -x +9 
Part B: Verify that these points satisfy the system of inequalities by substituting (x, y) for both points into both inequalities. [Pick any random point outside this shaded area to prove that it coordinates do not satisfy the system.] 
Graph the line y = -2x + 2. That will be a line that has a y-intercept of 2 and a slope of -2. Then shade *below* that line (we shade below because it is y < ...). The schools that will be in the shaded region are B, A, and D.
Hope this helps-Maranda