Which percent is equal to the given fraction?3/5


A.
3.5%

B.
30%

C.
35%

D.
60%

Answers

Answer 1
Answer: D) 60%. an easy way to do this would be to multiply the denominator and the numerator by the same thing to make the denominator equal 100, and the numerator is the percent. For example, this question, how many time can 5 go into 100? 20 times. multiply 20 by 3, because what you do to the denominator you have to do to the numerator; so 20 x 3 = 60, 60%.

3/8, multiply by 12.5, since 8 goes into a hundred 12.5 times, to get 8 x 12.5 = 100 and 3 x 12.5 = 37.5, 37.5%
Answer 2
Answer: The anwer is d,because a persent is always out of hundred so,multiply the denominator by 100

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What is sas congruence?

Answers

The SAS congruence is basically:
S- side
A- angle
S - side

If two triangles have two congruent sides and share one angle (or have one angle in between), then it (the triangles) are considered congruent.
s-side A-angle s-side

Help me please:)....

Answers

Answer:

In the pic

Step-by-step explanation:

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Tiffany pays $40 for 160 minutes of talk time on her cell phone. Hpw how many minutes of talk time does she get per dollar?

Answers

the answer is ............................4

a cylinder with base are 169π ft^2 and a height twice the radius. what is the lateral area and surface area of the cylinder

Answers

Area\ of\ base:A_B=169\pi\ ft^2\n\nA_B=\pi r^2\ \ \ (r-radius)\n\n\pi r^2=169\pi\ \ \ /:\pi\n\nr^2=169\n\nr=√(169)\n\nr=13\ (ft)\n\nH=2r\to H=2\cdot13=26\ (ft)

lateral\ area:A_L=2\pi rH\n\nA_L=2\pi\cdot13\cdot26=676\pi\ (ft^2)\n\nSurface\ area:A_S=2A_B+A_L\n\nA_S=2\cdot169\pi+676\pi=338\pi+676\pi=1014\pi\ (ft^2)
Area of base = 169 π 

r = √Area = 13 ft


Given, height = 2 x 13 = 26 ft.

Lateral surface area of cylinder = 2πrh = 2 x π x 13 x 26 = 676 π ft²

Total surface area = 2πr(r + h) = 2 x π x 13 x 39 = 1014 π ft²

Thus, lateral surface area is 676 ft² and total surface area is 1014 ft²

Using the graph of f(x) = log10x below, approximate the value of y in the equation 10y = 6

Answers

The given function is

f(x)= log 10 x

Taking base as 10

y=\log_(10)10 +\log_(10)x→→Using the property of, log a b= log a + log b

→y = 1 + \log_(10)x as, \log_(10)10=1

we have to approximate the value of y in the equation

→10 y = 6

→y=(6)/(10)

(6)/(10)= 1 + \log_(10)x  

\log_(10)x =  (-4)/(10)

x= (10)^{(-4)/(10)}=(10)^(-0.4)=0.398

Solving graphically,

we get , x= 0.398 for , y= (6)/(10)=.6

f(x) = ㏒(10x)
f(x) = ㏒₁₀(10x)

10y = 6
 10    10
    y = 0.6

f(x) = ㏒₁₀(10x)
0.6 = ㏒₁₀(10x)
10^(0.6) = 10x
10^{(3)/(5)} = 10x
\sqrt[5]{10^(3)} = 10x
\sqrt[5]{1000} = 10x
\frac{\sqrt[5]{1000}}{10} = x
(3.98)/(10) \approx x
0.398 \approx x

The fence along the length of a ranch measures 4,450.5 meters and the fence along the width of a ranch measures 2,890 meters.The length of the fence is how many kilometers longer than the width?



_______ km

Answers

Given:
Length = 4,450.5 meters
Width = 2,890 meters

1 kilometer = 1,000 meters

Length: 4,450.5 meters * 1km/1,000 meters = 4,450.5 km/1,000 = 4.4505km

Width: 2,890 meters * 1km/1,000 meters = 2,890 km/1,000 = 2.89 km

4.4505 km - 2.89 km = 1.5605 km

The length of the fence is 1.5605 km longer than the width of the fence.