Enter your answer as a mixed number in simplest form in the box.
hours
B.(7.5, –3.5) and (7.5, 3.5)
C.(7.5, 1.2) and (7.5, 2.3)
D.(7.5, –3.5) and (7.5, 7)
The points between whom the distance is 3.5 units apart are (7.5, 1.2) and (7.5, -2.3).
Given is to find the points between whom the distance is 3.5 units apart.
Using the distance formula for the points (7.5, 1.2) and (7.5, -2.3), we get-
d² = (- 2.3 - 1.2)² + (7.5 - 7.5)²
d² = (3.5)²
d = 3.5 units
Therefore, the points between whom the distance is 3.5 units apart are (7.5, 1.2) and (7.5, -2.3).
To solve more questions on functions, expressions and polynomials, visit the link below -
#SPJ6