Forty students are in fun club. Of those, 45% are girls. This percent increases to 56% after new girls join the club. How many new girls join? ~SwaggyAmerikanXO

Answers

Answer 1
Answer: 45% of 40 is 0.45×40=18 girls
if x girls join then 56% of 40+x is 0.56(40+x)=18+x
22.4+0.56x=18+x
put together like terms
4.4=0.44x
x=10 girls joined
Answer 2
Answer:

45% of 40 is 0.45×40=18 girls

if x girls join then 56% of 40+x is 0.56(40+x)=18+x

22.4+0.56x=18+x

put together like terms

4.4=0.44x

x=10 girls joined

Answer:


Step-by-step explanation:



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Round the number to the given place value. 1.044; hundredths    A.1.5  B.1.4  C.1.05  D.1.04i think it is D. Am i correct?
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How much money will you have if you started with $1200 and put it in an account that earned 7.3% every year for 10 years?

Answers

So an exponential equation is gonna be used for this problem. The formula for such is y=ab^x , in which the a variable is the initial value and the b variable is the growth/decay rate.

For this situation, 1200 is gonna be your a variable since you've started out with it. And as for your b variable, its gonna be 107.3%, or 1.073, since it's increasing.

Your equation should look like this: y=1200(1.073)^x and from here just plug in 10 into the x variable and solve.

Multiply (1.073)^10 (don't round answers until the end), and take that answer and multiply it with 1200, your answer should be $2427.61.

y=1200(1.073)^(10) \n y=2427.61

You have an initial amount of $45 in a savings account and you deposit an equal amount into the account each week. After 5 weeks the account holds $105. Write an equation that represents the amount yy (in dollars) of money in the account after xx weeks

Answers

y = 45+12x , this the answer

What's the sum of 74 836 and 2 67

Answers

If those are decimals the answer is 77. 506.
74,836 + 267 is 75,203

Hope this helps!

Use cramers rule to solve each system of equations : 6x = 2 - y
3x + 1 = 2y , please explain thank you :)

Answers

Answer:

just follow the rules

Step-by-step explanation:

Cramer's rule applies to the case where the coefficient determinant is nonzero. ... A simple example where all determinants vanish (equal zero) but the system is still incompatible is the 3×3 system x+y+z=1, x+y+z=2, x+y+z=3.

Write the system as a matrix equation. ...

Create the inverse of the coefficient matrix out of the matrix equation. ...

Multiply the inverse of the coefficient matrix in the front on both sides of the equation. ...

Cancel the matrix on the left and multiply the matrices on the right.

Which Function does NOT have an x-intercept?A.y=1/2x-7 B.y=-x^2+2x+5 C.y=-1/3x-5 D.y=x^2-2x+5

Answers

x intercept is when the line crosses the x axis aka when y=0

see if you can solve for x if you set y=0
if you get a false statement, then there is no yint
we can see that A and C have xints
test B and D

B.
0=-x^2+2x+5
if we put into quadratiic formula we get an x value


D. 0=x^2-2x+5
if we put into quadratic formula, there is not x intercept

D is answer

Hi Tarry


The answer is D


I am sorry that I can't show how to graph it but there is no x-intercept


I hope that's help !

When a 3 digit number is rounded to the nearest ten and to the nearest hundred, the answer is the same. What is one possible number that fits this rule?

Answers

The one possible number that fits this rule is 495

Step-by-step explanation:

Let us revise how we can round a number

1. When we round a number to the nearest ten we look to the one

digit if its 5 or greater than 5 we add the ten digit by 1 and put the

one digit 0, if the one digit less than 5 we keep the ten digit as it

and put the ones digit 0

2. When we round a number to the nearest hundred we look to the

ten digit if its 5 or greater than 5 we add the hundred digit by 1 and

put the ten and one digits 0, if the ten digit less than 5 we keep the

hundred digit as it and put the ten and one digits 0

Examples:

If 256 rounded to the nearest ten, then it will be 260

and if rounded to the nearest hundred, then it will be 300

If 543 rounded to the nearest ten, then it will be 540

and if rounded to the nearest hundred, then it will be 500

Now let us solve the problem

We are looking for 3 digit number when rounded to the nearest ten

and to the nearest hundred give the same answer

∴ Its unit digit must be 5 or greater than 5 to add ten digit by 1

∴ Its ten digit must be 9 because when we add 9 by 1 it will be 10

  and that mean the hundred digit will added by 1

- If The number is 495

∵ Its unit digit is 5

∴ When we round it to the nearest ten we will add the ten digit 9 by 1

∴ The ten digit will be 10 then we will add hundred digit by 1

∴ The hundred digit is 5 , ten digit is 0 and we will put the one digit 0

∴ The number after rounded to the nearest ten is 500

∵ When we round it to the nearest hundred we will look to the ten digit

∵ Its ten digit is 9

∴ We will add the hundred digit 4 by 1 and put the ten and one digits 0

∴ The number after rounded to the nearest hundred is 500

The one possible number that fits this rule is 495

Learn more:

You can learn more about rounding to significant figure in brainly.com/question/12445529

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