If f(x) is 4x-3 what is (f^-1of) (10)

Answers

Answer 1

Answer: $f(x)=4x-3\n y=4x-3\n 4x=y+3\n x=(1)/(4)y+(3)/(4)\n f^(-1)(x)=(1)/(4)x+(3)/(4)\n\n f^(-1) \circ f=(1)/(4)(4x-3)+(3)/(4)\n f^(-1) \circ f=(4x)/(4)-(3)/(4)+(3)/(4)\n f^(-1) \circ f=x$

Answer 2

Answer: $f(x)=4x-3\ \ \ \ and\ \ \ D_f=R\n\ny=4x-3\ \ \ \Rightarrow\ \ \ y+3=4x\ /:4\ \ \ \Rightarrow\ \ \ (1)/(4)y+ (3)/(4)=x\n\nf^(-1)(x)= (1)/(4)x+ (3)/(4) \ \ \ \ and\ \ \ \ D_(f^(-1))=R\n\n (f^(-1)\circ f) (10)=f^(-1)\bigg( f (10)\bigg)=\n=f^(-1)\bigg( 4\cdot10-3\bigg)=f^(-1)(37)=(1)/(4)\cdot37+ (3)/(4) =(37)/(4) +(3)/(4) = (40)/(4) =10$

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Rathan thinks all factors of even numbers are even. Which explains whether Rathan is correct? He is correct because the product of 2 and any number is even.
He is correct because the product of two even numbers is even.
He is incorrect because the product of an even number and an odd number is even.
He is incorrect because the product of two odd numbers is odd

Answers

The answer to this would be C, the third of the options. This is the only response that fully answers the question. For example, two factors of 42 would be 6 and 7, and both are not even, so given the absolute nature of Rathan's belief, there is no exception that can be made to make him correct. I hope this helps, and if it was sufficient to make you understand fully set it to the brainliest answer. Have a nice day! =)

The correct answer is:

He is incorrect because the product of an even number and an odd number is even.

Explanation:

When you multiply any number by an even number, whether it is even or odd, the product will be even.

This means that an even number can have an odd factor, and Rathan is incorrect.

Help please I need it asap

Answers

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Answers

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Ted weighs twice as much as Julie. Mike weighs three times as much as Julie. Together, Ted, Mike, and Julie weigh 210 lbs. What is the weight of each person?

Answers

x-weigh of Ted
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Answers

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Answers

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