Write an equation that is perpendicular to the line y = 2x + 13?

Answers

Answer 1
Answer: An equation can't be perpendicular to a line, but the graph of the equation can.

When that happens, we recall that the slopes of perpendicular lines are negative reciprocals.

One line is the graph of [ y = 2x + 13 ].  The slope of the line is 2 .
So the slope of a line perpendicular to it must be -1/2 .

The equation of a line perpendicular to it is:    y = (-1/2 x) plus (any number).

The y-intercept of the perpendicular line doesn't matter.  Only its slope does.
Answer 2
Answer: k:\ y=m_1x+b_1\ \ \ and\ \ \ l:\ y=m_2x+b_2\n\nk\perp l\ \ \ \Leftrightarrow\ \ \ m_1\cdot m_2=-1\n------------------------\n\nk:\ y=2x+13\ \ \ \ and\ \ \ \ l:\ y=m_2x+b_2\n\n2\cdot m_2=-1\ \ \ \Leftrightarrow\ \ \ m_2=- (1)/(2) \n\nl:\ y=- (1)/(2) x+b_2\ \ \ and\ \ \ b_2\ \in\ R\n\nfor\ example:\n\ny=- (1)/(2) x,\ \ \ y=- (1)/(2) x+5 (1)/(7) ,\ \ \ y=- (1)/(2)x - √(13)\ ,\ ...

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What is the product?(2x – 1)(x + 4) 2x2 – 4 2x2 + 4 2x2 + 7x – 4 2x2 – 7x – 4

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FACTOR AND SHOW STEP BY STEOP PLEASE

Answers

Step-by-step explanation:

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Which measure os greater 2 miles or 3 kilometers

Answers

Well, I do know that 2 miles covers a greater distance than 2 kilometers.

>>> The equation T^2 = A^3 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A, in astronomical units, AU. If planet Y is k times the mean distance from the sun as planet X, by what factor is the orbital period increased? <<

Answers

If planet Y is k times the mean distance from the sun than planet X, the right side of the equation becomes (kA)^3. which is k^3 times the left side, T^2. To equate both sides of the equation, multiply T by k^3/2 so that the left side becomes ((k^3/2) x T)^2 which simplifies into (k^3) x (T^2). Therefore, the answer is k^3/2. 

Answer:

Given the equation:

T^2 =A^3

shows the relationship between a planet's orbital period T and the planet's mean distance from the sun, A in Astronomical units

then:

For planet X:

Orbital period is:

T_(X) = (A)^{(3)/(2)}            .....[1]

As per the statement:

If planet Y is k times the mean distance from the sun as planet X.

⇒ A planet Y= kA mean distance from the sun as planet X.

then orbital period of Planet Y is:

T_(Y) = (kA)^{(3)/(2)}=k^{(3)/(2)}\cdot (A)^{(3)/(2)}    ....[2]

Divide equation [2] by [1] we have;

(T_(Y))/(T_(X)) = \frac{k^{(3)/(2)}\cdot (A)^{(3)/(2)}}{A^{(3)/(2)}}

Simplify:

(T_(Y))/(T_(X)) =k^{(3)/(2)}

or

T_(Y) =k^(3)/(2) T_X

Therefore, the orbital period is increased by factor k^(3)/(2)

Iceberg lettuce is grown and shipped to stores for about 30 cents a head, and consumers purchase it for about 72 cents a head. Find the percent increase.

Answers

The percent increase in sales of Iceberg lettuce is 140% .

What is profit percentage ?

Profit percentage are used to refer to the amount of profit that has been incurred in terms of percentage. It should also be stated that the profit percentage is one of the methods for comparing two quantities which the shopkeeper gets a profit.  

How to calculate percent increase of the given product ?

It is given that Iceberg lettuce is grown and shipped to stores for about 30 cents a head and consumers purchase it for about 72 cents a head.

Thus cost price of the product is 30 cents whereas the selling price is 72 cents.

Therefore, profit incurred is = (72 - 30) = 42 cents.

Percent increase -

=  (profit / cost price) * 100 %

= (42/30) * 100 %

= 140 %

Thus, the percent increase in sales of Iceberg lettuce is 140% .

To learn more about percent increase, refer -

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In this question, you divide the number it has increased, by original amount and times it by 100 to get the percent.

In this case, 72-30 = 42
42/30 = 7/5 
7/5 x 100 = 140%

I hope this makes sense!

jesse drives to work. The distance jesse's car travles (d) on a number of gallons of gas (g) is given y the equation d=15g.

Answers

you need to know what the distance jesse traveled is and then the number of gallons of gas she has then you plug it it.

distance equals 15 times the amount of gas in gallons
d=15g

Solve this inequality: 9h + 2 < –79.

Answers

The given expression of inequality can be solved as  h < -9.

What is linear inequality?

Linear inequality refers to the relation between a linear algebraic expression to some known value that contains inequality sign.

Unlike a linear equation it can have a range of values inside an interval.

The given inequality is as below,

9h + 2 < –79.

It can be solved as follows,

9h + 2 < –79

Subtract 2 from both sides to get,

9h + 2 - 2 < –79 - 2

⇒ 9h < -81

Divide by 9 on both sides as,

9h ÷ 9 < -81 ÷ 9

⇒ h < -9

Hence, the solution of the given inequality is h < -9.

To know more about linear inequality click on,

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9 h +2 < - 79 

9 h < - 79 - 2

9 h < -81

h < - 81 / 9

h < - 9

hope this helps!.