Which pair of fractions is equivalent to this pair? 2/9 and 3/7

Answers

Answer 1

Answer: an equivalent fraction for 2/9 is 4/18
and for 3/7 you have 6/14
I got it by multiplying both fractions by 2

Related Questions

What is the area of a triangle with a base of 5cm and height with 3cm
Which example supports the given conjecture? The sum of three odd numbers is an odd number.A. 3 + 5 + 7 = 15 B. 1 + 2 + 3 = 6 C. 2 + 4 + 8 =14D. 4 + 5 + 6 = 15 PLease HELP!
Please help thanks!!
Thirty is 12% of what number ?
5 to the third power times 25

If f(x) = 3x2 - 4 and g(x) = x +2, find (f-g)(x)

Answers

Answer:

3x^2 -x-6

Step-by-step explanation:

If f(x) = 3x^2 - 4 and g(x) = x +2

(f-g)(x)

I like to line them up vertically

3x^2 - 4

-( x +2)

----------------------

Distribute the minus sign

3x^2 - 4

- x -2

----------------------

3x^2 -x-6

You estimate that there are 44 marbles in a jar. The actual amount is 73 marbles. Find the percent error.

Answers

Answer:

Percentage Error in counting the marbles in the jar is 39.72%

Step-by-step explanation:

Estimated marbles in the jar = 44

Actual marbles in the jar = 73

⇒Error in Marbles = Number of actual Marbles - Estimated marbles

= 73 - 44 = 29

So, the error in counting marbles in the jar is 29.

Now, $\textrm{Percentage Error} = \frac{\textrm{Error in the Data}}{\textrm{Actual Data}} * 100$

= $(29)/(73) * 100 = 39.72$

or, Percentage Error = 39.72%

Hence, the Percentage Error in counting the marbles in the jar is 39.72%

A street light bulb is fixed on a pole 6m above the level of the street. If a women of height 1.5m casts a shadow of 3m, find how far is she away from the base of the pole

Answers

The woman's shadow length is 2 times her height, so her distance from the light is 2 times the difference in height between her and the light bulb.

2×(6 m - 1.5 m) = 9 m

_____
A diagram can help you see the similar triangles.

a team was given a bucket of water and a sponge. The team had 1 minute to fill an empty half gallon bucket with water using only the sponge.

Answers

I don't exactly see the question here so therefore I can't answer it

Given AABC. m LA= 39°
MLB=104°
AC= 20cm
mLC=
AB =
CB -

Answers

Answer:

∠C = 37° ,

AB = 26.54 cm ,

BC= 33.27 cm

Step-by-step explanation:

Given that in triangle ABC

∠A = 39° AC = 20 cm

∠B = 104°

∵ sum of all the three angles of triangle = 180°

So, ∠C = 180° - ( ∠A + ∠B)

∠C = 180° - (39° + 104°)

∠C = 37°

Now Tan 37° = $(AC)/(AB)$

Or, AB = $(20)/(tan 37°)$

So, AB = 26.54 cm

Again, Sin 37° = $(AC)/(BC)$

So, BC = $(20)/(sin 37°)$

Or, BC = $(20)/(0.601)$

∴ BC= 33.27 cm

Hence ∠C = 37° , AB = 26.54 cm , BC= 33.27 cm Answer

Three vertices of a rectangle are (–3, 4), (5, 4), and (5, –2).

What are the coordinates of the fourth vertex of the rectangle?

A. (–3, –4)

B. (–3, –2)

C. (5, –3)

D. (5, 2)

Answers

$A =(-3, 4), \ \ B= (5, 4),\ \ C= (5, -2)\n \n The \ slope \ of \ AB : \n \n \n m= (y_(2)-y_(1))/(x_(2)-x_(1) ) = (4-4)/(5+3)=(0)/(8)=0\n \n The \ slope \ of \ CB :\n \n m= (y_(2)-y_(1))/(x_(2)-x_(1) ) = (5-5)/(-2-4)=0$

$The \ slope \ of \ lines \ parallel \ is \ the \ same \n \nTo \ find \ the \ coordinates \ of \ the \ fourth \ vertex, \ add \ the \ coordinates \n of \ A \ and \ C \ together, \ and \ subtract \ the \ coordinates \ of \ B. \n \n The \ fourth \ vertex \ is: (-3+5-5; 4-2-4) = (-3, -2) \n \n Answer: \ B. \ \ (-3, -2)$

The rectangle doesn't necessarily have to be standing up straight or laying down flat
on the graph. It could be tilted ... leaning. Dealing with those coordinates would be
a nightmare, and since you're in Middle School and just learning this stuff, we can be
pretty sure that the rectangle in this problem is straight on the graph.

If we think about it for a second, and visualize a rectangle in our mind, we realize that:

-- Both top corners have the same y-coordinate.
-- Both bottom corners have the same y-coordinate.
-- Both corners on the left side have the same x-coordinate.
-- Both corners on the right side have the same x-coordinate.

The first two points given in the question are ( -3, 4) and (5, 4).

-- They have the same y-coordinate, so they must be either the top
or the bottom two corners.

-- We also know right away that the left side of the rectangle is at x = -3
and the right side of the rectangle is at x = 5 .

Now look at the third given point ... (5, -2) .

-- Its x-coordinate is 5 so we know it's a corner on the right side.

-- But we already had one corner on the right side ... the point at (5, 4).
This new one is lower.

-- So now we know that (5, 4) was the upper right corner, (-3, 4) was the
upper left corner, and this new point is the lower right corner.

All we're missing is the lower left corner.

We know now that the left side is at x = -3 and the right side is at 5 .
We also know now that the top is at y = 4 and the bottom is at y = -2 .

So the bottom left corner is (-3, -2). That's choice - 'B' .

Other Questions

Carl has three lengths of cable. 5/6 yard long, 1/4 yard long, and 2/3 yard long. He needs at least 1 yard of cable. After Carl has used 1 yard of cable, how much cable will he have left? Explain how you found your answer.

4 cm 2cm 2cm 4 cm what’s the area?

Identify the domain of the function shown in the graph.

The student union at school has MP3 players pre-loaded with audio and digital books to check out. When the student starts downloading new books at 9:00 am, there are 15 already loaded. When he checks at noon, there are 30 books completely loaded. Assuming that the computer downloads books at a consistent rate, how many complete books will have downloaded at 3:00 pm?Write a function of books downloaded, y, based on time passed, x (in hours), as well as the total number of books that will be completed by 3:00 pm. A y = 10x + 5; 45 complete books B y = 15x + 15; 65 complete books C y = 5x + 15; 45 complete books D y = 15x + 10; 100 complete books