Whats the y intercept of y= 1/2 log(x+1)-log(2x+10)

Answers

Answer 1
Answer: y=(1)/(2)log(x+1)-log(2x+10)\n\ny\ intercept\ for\ x=0:\n\n(1)/(2)log(0+1)-log(2\cdot0+10)=(1)/(2)log1-log10=(1)/(2)\cdot0-1=-1\n\nAnswer:y=-1,\ the\ point\ is\ (0;-1).
Answer 2
Answer: y = 1/2 log(x + 1) - log(2x + 10)

The y-intercept of any graph is the point where x=0.

y = 1/2 log(0 + 1) - log(0 +10)

y = 1/2 log(1) - log(10)

log(1) = 0
log(10) = 1

y = 1/2 (0) - 1

y = -1

That's all there is to it.  I'll bet you totally froze when you saw all those logs.

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The grocery store sells kumquat for $4.50 a pound and Asian pears for $3.75 a pound write an equation in standard form for the weight of kumquat k and Asian pears p that a customer could buy with $16

Answers

Answer:

let k represents the kumquat weight(in pound) and p represents the Asian pears weight respectively.

As per the given conditions,

The grocery store sells kumquat for $ 4.50 a pound

⇒ for 1 pound \rightarrow $4.50

then, in k pound  = 4.50 k

similarly,

The Asian pears for $3.75 a pound

⇒ for 1 pound \rightarrow $3.75

then, in p pound  = 3.75 k

Standard form of the equation is in the form of  Ax + By = C:

The weight of kumquat k and Asian pears p that customer could buy with $ 16,

then the standard form of equation is: 4.50k +3.75p = 16

1 pound kumquat = 4.50
1 pound pear = 3.75
4.50k + 3.75p = 16

Simplify 2a2b3(4a2 + 3ab2 – ab) = ? A. 8a4b3 + 6a3b5 + 2a3b4
B. 8a4b3 + 6a3b5 – 2a3b4
C. 8a4b5 + 3a3b5 – 2a3b4
D. 8a4b5 + 3a3b5 + 2a3b4

Answers

2a²b³(4a² + 3ab² - ab)
2a²b³(4a²) + 2a²b³(3ab²) - 2a²b³(ab)
8a⁴b³ + 6a³b⁵ - 2a³b⁴

The answer is B.

Which shows a perfect square trinomial?50y2 – 4x2
100 – 36x2y2
16x2 + 24xy + 9y2
49x2 – 70xy + 10y2

Answers

Answer:

C. 16x^2+24xy+9y^2

Step-by-step explanation:

We have been given 4 expressions and we are asked to choose the expression that is a perfect square trinomial.

We know that a perfect square trinomial is in form: a^2+2ab+b^2.

Upon looking at our given choices we can see that option C is the correct choice as we can write as:

16x^2+24xy+9y^2=(4x)^2+2(4x\cdot 3y)+(3y)^2

16x^2+24xy+9y^2=(4x)^2+2(12xy)+(3y)^2

16x^2+24xy+9y^2=(4x)^2+24xy+(3y)^2

Therefore, option C is the correct choice.

A perfect square trinomial is found in the expression where both the leading coefficients and the constant are both perfect squares. That only is the case with the third choice above. 16 is a perfect square of 4 times 4, and 9 is a perfect square of 3 times 3. We need to set it up into its perfect square factors and FOIL to make sure, so let's do that. Not only is 16 a perfect square in that first term, but so is x-squared. Not only is 9 a perfect square in the third term, but so is y-squared. So our factors will look like this:

(4x + 3y)(4x + 3y). FOIL that out to see that it does in fact give you back the polynomial that is the third choice down.

There are a total of 126 people in a group. One person in seven has a cat for a pet. How many people do not have a cat?

Answers

Try 126 divided by 7. Then, do 128 minus the answer to 126 divided by 7.
I will say 17 people don't have a cat for a pet

Can you help ? me solve this question ?

Answers

Answer:

x {222}^(2)

PLEASE HELP!! i’m so confused.

Answers

Answer:

[A] -0.5

General Formulas and Concepts:

Algebra I

  • Reading a coordinate plane
  • Coordinates (x, y)
  • Functions
  • Function Notation

Algebra II

  • Piecewise Functions

Calculus

Limits

Graphical Limits

Discontinuities

  • Removable (Hole)
  • Jump
  • Infinite (Asymptote)

Step-by-step explanation:

Step 1: Define

Identify

\displaystyle f(x) = \left \{ {{-1 - x, \ x \neq 2} \atop {8, \ x = 2}} \right.

\displaystyle  \lim_(x \to -0.5) f(x)

Step 2: Solve

According to the graph, we see that when we approach x = -0.5 of the function f(x), we land on y = -0.5.

The function value at x = 2 would equal 8, but the limit as x approaches -0.5 would not approach the function value, but approach the hole in the function.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

Book: College Calculus 10e