What number is greater than 714587

Answers

Answer 1

Answer: A number greater than 714587 is 714588 and any number above that.

Answer 2

Answer: well there are many numbers greater than 714587 so the numbers that are greater than 714587 is 714588 to infinity

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What is 2 and 928 ten-thousandths as a decimal?

Answers

I think this is the correct answer
2+ 928 = 2 + 0.0928 = 2.0928
---------
10000
I hope i helped you :-)

There are 7 people at a party. If each person shakes the hand of everyone exactly once, how many handshakes will take place

Answers

Call the number of people $n$ .

Looking at the first person, they can shake hands with $n-1$ other people (since they can't shake hands with themselves.)

For the second person, they can shake hands with $n-2$ other people. (They can't shake hands with themselves and they already shook with Person 1, on Person 1's turn.

If we carry on this way we see that the total number of shakes is given by:
$(n-1)+(n-2)+...+2+1$ which simplifies to: $(n(n-1))/(2)$ .

For $n=7$ we then have:
$S=(7(7-1))/(2)=(7(6))/(2)=(42)/(2)=21$
OR
$S=(7-1)+(7-2)+(7-3)+(7-4)+(7-5)+(7-6)=6+5+4+3+3+2+1=21$

There will be 42 handshakes

How many times greater is one hour than one minute

Answers

60 time because one hour has 60 minutes

60 mins or 59 mins hoped i helped

A rectangle of perimeter 100 units has the dimensions shown. Its area is given by the function A = w(50 - w). What is the GREATEST area such a rectangle can have? The rectangle shown has 50-w on the top and bottom.
and a w on its left side and right side.

Answers

Answer:

The greatest area of rectangle is:

625 square units.

Step-by-step explanation:

It is given that:

A rectangle of perimeter 100 units has the dimensions as:

50-w on the top and bottom.

and a w on its left side and right side.

i.e. we may say the length of the rectangle is:

50-w

and the width of the rectangle is:

Now, we need to find the greatest area of rectangle.

As the area of rectangle is:

A = w(50 - w)=50w-w^2

Now, to find the maximum area we differentiate the Area with respect to the width as:

$(dA)/(dw)=0\n\ni.e.\n\n50-2w=0\n\n50=2w\n\nw=25$

Hence, to obtain the maximum area the width of the rectangle is: 25 units.

and that of the length of the rectangle is:

50-25=25 units.

Hence, the dimensions of rectangle in order to obtain the maximum area is:

25 units by 25 units.

So, the area of rectangle is:

$Area=25* 25\n\nArea=625\ \text{square\ units}$

Hence, the greatest area of rectangle is:

625 square units.

disregard the w and w-50 for now
to have the greatest area, try to make legnth and width the same
P=100
P=2(L+W)
100=2(L+W)
50=L+W
if L=W
50=L+L
divide 2
25=L=W

A=LW=25*25=625

greatest is 625 square units

What greater than 1/3

Answers

I think the The answer 1/1 or1/2! If it is not correct then ask some one else

2/3 IS GREATER THAN 1/3 AND SO IS 3/3. SORRY ABOUT CAPS.

leila and jo are two of the partners in a business.leila makes $3 in profits every $4 that jo makes.if jo makes $60 profit on the first item they sell,how much profit does leila make?

Answers

3/4=x/60 so you divide 60 by 4 and get 15x3=45/60

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