Which statement describes a reversible reaction at equilibrium?(1) The activation energy of the forward reaction must equal the activation energy of the reverse reaction.
(2) The rate of the forward reaction must equal the rate of the reverse reaction.
(3) The concentration of the reactants must equal the concentration of the products.
(4) The potential energy of the reactants must equal the potential energy of the products.

Answers

Answer 1
Answer:

Answer: The correct answer is Option 2.

Explanation:

Reversible reaction is defined as the reaction in which the products formed react together to give the reactants back. For general reversible chemical equation:

aA+bB\rightleftharpoons cC+dD

At equilibrium, the rate of forward reaction is equal to the rate of backward reaction.

Rate of forward reaction:k[A]^a[B]^b

Rate of backward reaction:k[C]^c[D]^d

At equilibrium, k[A]^a[B]^b = k[C]^c[D]^d

Thus, the correct answer is Option 2.

Answer 2
Answer: When a reaction has reached Equilibrium, the rate of the forward reaction is equal to that of the backward reaction.

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State one reason that cells are small!

Answers

cells are so small so the surface area and volume of them can be proportional to each other. This helps with the efficiency of the cell's absorption and waste expulsion processes. 

A fish may have hundreds of offspring at a time and only a small number can survive. which characteristics of fish might allow them to survive

Answers

Well depends on what type of fish the parent is but i guess you can say:
what they eat
teeth
instincts
color
venom
blending in,etc

How many liters of CO2 form at STP if 5.0 g ofCaCO3 are treated with excess hydrochloric acid?

Answers

Answer: STP

CaCO3 = 5 g

Convert gram to mol

100 g of CaCO3   = 1 mol

5 g of  CaCO3 (n)  = 5 g *(1 mol/100 g) = 0.05 mol

Gas law  

PV =nRT

V = nRT/P  

V = (0.05 mol * (0.08206 L atm /K mol) *273 K)/1 atm

V = 1.124 L

Explanation:

Final answer:

When 5.0 g of CaCO3 are treated with excess hydrochloric acid, it forms 1.118 L of CO2 gas at STP.

Explanation:

When 5.0 g of CaCO3 is treated with excess hydrochloric acid, it undergoes a chemical reaction and forms CO2 gas. To find the number of liters of CO2 formed at STP (standard temperature and pressure), we need to use the ideal gas law. The molar mass of CaCO3 is 100.09 g/mol, and 1 mol of CaCO3 produces 1 mol of CO2 gas. The volume of 1 mol of any gas at STP is 22.4 L. Therefore, we can calculate the number of moles of CaCO3, then convert it to moles of CO2 and finally to the volume of CO2 gas in liters.

Using the given information, we have:
Mass of CaCO3 = 5.0 g
Molar mass of CaCO3 = 100.09 g/mol
Moles of CaCO3 = Mass of CaCO3 / Molar mass of CaCO3
Moles of CO2 = Moles of CaCO3
Volume of CO2 at STP = Moles of CO2 * 22.4 L/mol

Plugging in the values, we get:
Moles of CaCO3 = 5.0 g / 100.09 g/mol = 0.04997 mol
Moles of CO2 = 0.04997 mol
Volume of CO2 at STP = 0.04997 mol * 22.4 L/mol = 1.118 L

Learn more about Volume of CO2 gas formed here:

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#SPJ2

How many days are in a solar year?

Answers

365 days.

Solar years is what we go by.

the answer is 365.242

Select the correct answer.If a silver nitrate solution is added to excess sodium sulfide, this reaction takes place: 2AgNO3(aq) + Na2S(aq) → Ag2S(s) + 2NaNO3(aq).
Suppose you use 0.0150 liter of a 2.50 M solution of silver nitrate. Assuming the reaction goes to completion, how much silver sulfide is produced? Use the periodic table.
A. 1.49 g
B. 4.65 g
C. 9.30 g
D. 18.6 g

Answers

Answer:- B. 4.65 g.

Solution:- The given balanced equation is:

2AgNO_3(aq)+Na_2S(aq)\rightarrow Ag_2S(s)+2NaNO_3(aq)

It asks to calculate the mass of silver sulfide formed by when 0.0150 liters of 2.50 M of silver nitrate are used.

Moles of silver nitrate are calculated on multiplying it's liters by its molarity and then on multiplying by mol ratio, the moles of silver sulfide are calculated. These moles are multiplied by the molar mass to convert to the grams.

Molar mass of Ag_2S = 2(107.87)+32.06  = 247.8 g per mol

The dimensional set up for the complete problem is:

0.0150L((2.50molAgNO_3)/(1L))((1molAg_2S)/(2molAgNO_3))((247.8gAg_2S)/(1molAg_2S))

= 4.65gAg_2S

So, the correct choice is B. 4.65 g.


Answer:

that jawn gon be 4.65 g

4. The average kinetic energy of water molecules is greatest inO liquid water at 273 K
O ice at 0°C
O liquid water at 90°C
O steam at 100°C

Answers

The average kinetic energy of water molecules is greatest in steam at 100°C.

Kinetic energy of water

Water is a polar solvent that has potential energy on its own which can be converted to kinetic energy once the water is in motion.

The kinetic energy is that energy that a moving body possesses.The faster a molecule moves, the more kinetic energy it has, and the higher the measured temperature.

That being said, when the temperature of water is increased, there would be increased molecular motion leading to a higher kinetic energy.

Therefore, the average kinetic energy of water molecules is greatest in steam at 100°C.

Learn more about kinetic energy here:

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Answer:

steam at 100°C

Explanation:

Grandpoint approved