The equation y = 16x 560 describes the number of calories in a recipe, where y is the total number of calories and x is the number of teaspoons of sugar added. The table shows the number of calories in another recipe, where y is the total number of calories and x is the number of teaspoons of honey added.How many calories are in a teaspoon of sugar, and how many are in a teaspoon of honey?
Teaspoons of honey 1 2 4 7
Total calories 504 568 696 888
A teaspoon of sugar has____ calories.
A teaspoon of honey has____ calories
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a teaspoon of sugar = 1 teaspoon of sugar = 560+16 = 576 cal
y = 16x + 560 calories
y=64x+440 calories
Add them and that's how you check. :)
(If that doesn't make sense, Sugar has 16 Cal. and Honey has 64 Cal.)
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I am a quadrangleI have 2 pairs of parallel sidesall of my angles are right anglesI am not a square
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Answers
Answer:To solve the equation 4x + 17/18 - 13x - 2/17x - 32 + x/3 = 7x/12 - x + 16/36, we can follow these steps:
1. Combine like terms on each side of the equation.
On the left side, we have 4x - 13x + x/3. Simplifying this, we get -8x + x/3.
On the right side, we have 7x/12 - x + 16/36. Simplifying this, we get -5x/12 - x + 4/9.
2. Get rid of any fractions by multiplying each term by the least common denominator (LCD).
The LCD of 3, 12, and 36 is 36. Multiply each term on both sides of the equation by 36 to eliminate the fractions.
3. Simplify and combine like terms.
On the left side, we have -8x + x/3, which becomes -24x + x^2/3 after multiplying by 36.
On the right side, we have -5x/12 - x + 4/9, which becomes -15x - 3x + 16 after multiplying by 36.
4. Move all terms to one side of the equation.
Combining like terms, we get -24x + x^2/3 = -18x + 16.
5. Multiply the entire equation by 3 to eliminate the fraction.
This gives us -72x + x^2 = -54x + 48.
6. Move all terms to one side of the equation again.
Combining like terms, we get x^2 + 18x - 48 = 0.
At this point, the equation is a quadratic equation. To solve it, we can either factor or use the quadratic formula.
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Explanation: 30/7=x/3
90=7x
90/7=12.85...
X=12.9 when rounded to nearest tenth
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x^2 - x - 30 = 0
We need two numbers whose sum is -1 and whose product is -30. In this case, it would have to be 5 and -6. Therefore we can also write our equation in the factored form
(x + 5)(x - 6) = 0
Now we have a product of two expressions that is equal to zero, which means any x value that makes either (x + 5) or (x - 6) zero will make their product zero.
x + 5 = 0 => x = -5
x - 6 = 0 => x = 6
Therefore, our solutions are x = -5 and x = 6.
= 3
why is this incorrect?
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Let x represent , then you can rewrite the expression as 3x - x.
3x - x = 2x. Now replace "x" with and you get 2
.
The reason 3 is incorrect is because you are supposed to perform the operation (+, -, x, ÷) with the coefficients, not with the variable or radical.
Algebraically, you have to factor the square root of 7 to see why you're wrong:
Conceptually, think that any object - say an apple - represents the square root of seven.
So, you have three apples, and you take away one apple. You have two apples remaining, i.e.