How would you solve this problem?

Answers

Answer 1

Answer: The first and most important series of steps in pursuing an answer to this particular problem is:

1). Obtain a clear printed copy of the problem.

2). Spread the copy in front of you.

3). Look at the entire copy and center it in your field of view.

4). (the climax of these preliminaries): READ the problem, as many times as neccessary to understand what information it gives, and what exactly it asks.

Obviously, we're not equipped to do any of this for you.

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every three days Seth goes to the grocery store every brain goes to the store every 5 days what day will they both go

Answers

If seth goes every three days and Brian im assuming is the name.Goes every five days then they will both go on day 15

Just multiply 3x5 which is 15

The mass of Hinto's math book is 4,458 grams, what is the mass of 4 math books in kilograms

Answers

The weight of 4 math books is 17.832 kilograms.

Given:
weight of math books = 4458 grams
number of math books = 4

1 kg = 1000 grams

4458 grams * 1kg/1000 grams = 4458 kg/1000 = 4.458 kg
4.458 kg * 4 books = 17.832 kg

OR

4458 grams * 4 books = 17832 grams
17832 grams * 1kg/1000 grams = 17832 kg/1000 = 17.832 kg

2. Find the value of x to the nearest tenth.a. 4.5
b. 5.4
c. 6.3
d. 7.2

3. Find the value of x.
a. 7
b. 7.5
c. 8
d. 8.5

4. FG ⊥ OP, RS ⊥ OQ. FG=40, RS=40, OP=15. Find x.
a. 15
b. 17
c. 20
d. 21

5. Find the value of x to the nearest tenth.
a. 7.5
b. 7.9
c. 8.1
d. 8.9

Answers

Answer:

Part 2) Option b. 5.4

Part 3) Option c. 8

Part 4) Option a. 15

Part 5) Option d. 8.9

Step-by-step explanation:

Part 2) Find the value of x to the nearest tenth

we know that

x is the radius of the circle

Applying the Pythagoras Theorem

$x^(2)=3.6^(2)+(8/2)^(2)$

$x^(2)=28.96$

$x=5.4\ units$

Part 3) Find the value of x

In this problem

x=8

Verify

step 1

Find the radius of the circle

Let

r -----> the radius of the circle

Applying the Pythagoras Theorem

$r^(2)=8^(2)+(15/2)^(2)$

$r^(2)=120.25$

$r=√(120.25)$

step 2

Find the value of x

Applying the Pythagoras Theorem

$r^(2)=x^(2)+(15/2)^(2)$

substitute

$120.25=x^(2)+56.25$

$x^(2)=120.25-56.25$

$x^(2)=64$

$x=8\ units$

Part 4) Find the value of x

In this problem

x=OP=15

Verify

step 1

Find the radius of the circle

Let

r -----> the radius of the circle

In the right triangle FPO

Applying the Pythagoras Theorem

$r^(2)=15^(2)+(40/2)^(2)$

$r^(2)=625$

$r=25$

step 2

Find the value of x

In the right triangle RQO

Applying the Pythagoras Theorem

$25^(2)=x^(2)+(40/2)^(2)$

$625=x^(2)+400$

$x^(2)=625-400$

$x^(2)=225$

$x=15\ units$

Part 5) Find the value of x

Applying the Pythagoras Theorem

$6^(2)=4^(2)+(x/2)^(2)$

$36=16+(x/2)^(2)$

$(x/2)^(2)=36-16$

$(x/2)^(2)=20$

$(x/2)=4.47$

$x=8.9$

erika has 3 pieces of ribbon.each piece id 25 yards long.she needs to cut pieces that are 22 inches long.what is the greatest number of 22 inch pieces she can cut from the three pieces of ribbon?

Answers

there is 900in in 25 yards so 900*3=2700/22=122.7
so it will be 122 pieces

Classify the following triangle

Answers

Answer:

B acute

D equilateral

Step-by-step explanation:

All the sides are equal (line in the middle of each side) = equilateral

All the angles are equal (single line in each angle) = equilangular

That means 180/3 = 60

Each angle is 60 degrees 60 degree angles are acute

What is 8.89 rounded to the nearest tenth

Answers

9
There is .Tenths hundreths and so on behind the decimal they skip ones
~Riley
4 or less let it rest 5 or more raise the score that how I remember it

the correct answer is 9.00 because after the 1st 8 that number is higher than 4 so you go up a number

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Find the circumference of a circle with an area of 254.47 square inches.

What is 755,082 rounded to nearest ten thousand

Jeremy drew a polygon with four right angles and four sides with the same length. Name all the polygons that he could have drawn.