How do I solve this complex multi-step equation 2x + (-2 )= 10x - 4 ?
Month 5 is when they're even
Answer:
I really want to help you but I am really confused with those topics. I am very sorry.
Step-by-step explanation:
Answer: no
Step-by-step explanation:
Answer:
See below
Step-by-step explanation:
Lets label the consecutive odd numbers as 2n+1 and 2n+3 where n is an integer.
We need to prove that
((2n + 3)^2 - (2n + 1)^2 is a multiple of 8.
Using the difference of 2 squares on the left side:-
(2n + 3 + 2n + 1)(2n + 3 - (2n + 1)
= (4n + 4)(2)
= 8n + 8 which is a multiple of 8
The difference between squares of consecutive odd numbers can be expressed as 4n+4 which is a multiple of 8.
Let's take two consecutive odd numbers. We can express an odd number as 2n+1 where n is any integer. So, the consecutive odd number will be 2n+3 (adding 2 to the previous one).
Now, the squares of these consecutive numbers are (2n+1)² and (2n+3)² respectively.
The difference between these squares is (2n+3)² - (2n+1)². Applying the formula a² - b² = (a+b)(a-b), we get 4n+4 as the answer which is a multiple of 8 as 8 divides it without a remainder.
So the difference between the squares of consecutive odd numbers is a multiple of 8.
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