Gretchen is using an overhead projector to enlarge a drawing so she can make a poster. The original drawing measures 60 mm wide by 80 mm high. She moves the projector so that the width of the projected image is 300 mm. If the original drawing and the projected image are similar figures, what will be the height of the projected image?
A. 225mm
B. 440mm
C.180mm
D. 400mm
how do I graph: 12.50x + 6.25y ≥ 1500? Thank you!
A.) 7
B.) 12
C.) 27
D.) 81
Hello from MrBillDoesMath!
Answer:
Choice D, 81
Discussion:
By log 3x = 4 I presume that "3" is the base not a multiplier of x. Assuming it is the base, then the equation is equivalent to
x = 3^4
= 81
This is Choice D.
Thank you,
MrB
Answer:
it's D
Step-by-step explanation:
i did the test
Answer:
y= -1/2x
Step-by-step explanation:
Equation of the line is always in the form y=mx + c
where c is the y-intercept ( where the graph crosses the y-axis) and m is the gradient.
The straight line passes through the origin which are the points (0,0) hence
gradient= change in y÷ change in x
G= -2-0 ÷ 4-0 =-2÷4= -1/2x
y= 1/2x+c
-2=-1/2(4)+c
-2=-2+c
-2+2=c
c=0
∴ the equation of the line is y=-1/2x
The equation of the line passing through the origin and the point A(4,-2) is y = -0.5x.
In Mathematics, the equation of the line can be found using the point-slope form which is y = mx + c, where 'm' is the slope of the line and 'c' is the y-intercept. Since the line passes through the origin O(0,0), the y-intercept 'c' is 0. The slope 'm' of the line is found by the formula 'change in y/change in x'. Given the point A(4,-2), the change in y (the difference in the y-values of your two points) is -2 - 0 = -2, and the change in x (the difference in the x-values of your two points) is 4 - 0 = 4. Therefore, the slope 'm' is -2/4 = -0.5.
Substitute 'm' and 'c' values in the equation y = mx + c, we get the equation of the line OA as y = -0.5x.
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