we know that
In an Arithmetic Sequence the difference between one term and the next is a constant
This problem is an Arithmetic Sequence
where
the first term is
and
the common difference is
In general we can write an Arithmetic Sequence as a rule
where
a1 is the first term
d is the common difference
so
Find the term a7
therefore
the answer is
both variables are x
pretend there is an imaginary 1 in front of the x for x squared
3 x 1 = 3
x^2 x X = x^3
this is because when multiplying numbers with the same variable like this problem for instance then you add the squared (2) with the x ( imaginary 1)
so 3x^3 is the answer
The expression 3x times x squared simplifies to 3x³.
We have,
To simplify the expression 3x times x squared, you can multiply the coefficients and combine the variables.
The expression can be written as:
To multiply the coefficients, you multiply 3 and 1, which gives you 3.
To combine the variables, you multiply the x term and the x² term.
When multiplying variables with the same base (in this case, x), you add the exponents. So, can be simplified as
Putting it together, the expression 3x times x squared simplifies to 3x³.
Thus,
The expression 3x times x squared simplifies to 3x³.
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By using the concept of reciprocal of fraction, the result obtained is -
Reciprocal of is
What is reciprocal of a fraction?
At first, it is important to know about fraction.
Suppose there is a collection of objects and a part of the collection has to be taken. The part which is taken is called fraction. In other words, part of a whole is called fraction.
The upper part of the fraction is called numerator and the lower part of the fraction is called denominator.
For example: is a fraction. Here, 4 is the numerator of the fraction and 7 is the denominator of the fraction.
Let p be a fraction. Reciprocal of p is a fraction in which if the fraction is multiplied by p, the result obtained is 1 (multiplicative identity)
Here,
Let the reciprocal of be x
Reciprocal of is
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£360 in the ratio 1 : 8
1
B.
6
C.
10
D.
15