A car initially at rest, accelerates at a constant rate of 4.0 m/s for 6s. How fast will the car be traveling at 6s

Answers

Answer 1
Answer: it will be traveling exactly 24 miles per hour 
Answer 2
Answer:

Final answer:

The final velocity of the car can be found using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Plugging in the given values, we find that the car will be traveling at 24 m/s at 6 seconds.

Explanation:

To find the final velocity of a car accelerating at a constant rate, we can use the equation:
v = u + at

Where:
v is the final velocity, u is the initial velocity (which is zero in this case), a is the acceleration (4.0 m/s²), and t is the time (6 seconds).

Plugging in the values, we get:
v = 0 + (4.0 m/s²)(6s) = 24 m/s

Therefore, the car will be traveling at 24 m/s at 6 seconds.

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Find two words in a vocabulary list that descirbe the bending of a wave

Answers

reflection and refraction 


refraction and reflection describe a wave

Problem 5. A bullet leaves a rifle with a velocity of 452 m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 0.93 m. Determine the acceleration of the bullet.

Answers

Answer:

1.1 x 10⁵m/s²

Explanation:

Given parameters:

Velocity  = 452m/s

distance  = 0.93m

Unknown:

Acceleration of the bullet  = ?

Solution:

To solve this problem, we use one of the kinematics equation which is given below:

           V² = U²  + 2aS

V is the final velocity

U is the initial velocity  = 0m/s

a is the unknown acceleration

S is the distance traveled  

 So;

          452²   = 0²  + (2 x a x 0.93)

          204304  = 1.86a

               a  = 1.1 x 10⁵m/s²

Final answer:

The acceleration of the bullet in the gun barrel can be calculated using the kinematic equation for motion. By substituying the given values into the equation, we find the acceleration to be approximately 1.095 x 10^5 m/s^2.

Explanation:

The subject of this question is Physics, specifically a topic under mechanics known as kinematics. The problem given can be solved using kinematic equations which are used to describe the motion of an object without considering the forces that cause it to move. In this case, the final velocity (vf) of the bullet is given as 452 m/s, the initial velocity (vi) is assumed to be 0 as it starts from rest, and the distance (d) is given as 0.93 m. We are asked to determine the value of acceleration (a).

Using the kinematic equation vf2 = vi2 + 2ad and substituting the given values, we get (452 m/s)2 = 0 + 2*a*0.93 m. We can rearrange to solve for acceleration to get: a = (452 m/s)2 / (2*0.93 m) = 109523.66 m/s2.

So, the acceleration of the bullet in the gun barrel is approximately 1.095 x 105 m/s2.

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What is the most common state of matter in the universe

Answers

Answer:

Plasma

Explanation:

Plasmais the most common because plasma is a gas that has been energized to the point that some of the electrons break

When a squid pushes against the water, the squid moves forward because the ______________ pushes against the _______________.​

Answers

Answer:

water pushes against the squid

Which of the following helps support the argument that light behaves like a particle? A. Sound, which travels in waves, can't travel through a vacuum.
B. Interference is observed with light.
C. Diffraction is observed with light.
D. Unlike sound, light waves don't need a medium to self-propagate

Answers

The correct answer to the question is : D) Unlike sound, light waves don't need a medium to self-propagate

EXPLANATION:

Before coming into any conclusion, first we have to understand the nature of sound and light.

A sound wave is a longitudinal wave which requires a medium for its propagation.  It can not move in space as space contains no material medium for its propagation.

Light is normally considered as electromagnetic wave which does not require any medium for its propagation. It can travel in space also.

The interference and diffraction can not be explained by the particle nature of light.

Hence, the argument that partially support that light behaves just like a particle is the last statement i.e Unlike sound, light waves do not need a medium to self-propagate.

 Sound, which travels in waves, can't travel through a vacuum. 

As there is no matter in vacuum then sound cannot be transmitted. But the transmission of light is quite different, its particle and wave nature is well suited for travel in vacuum.

In the World Pond Hockey tournament held in Plaster Rock, NB, a puck on the ice travels 20.0 m [25° W of N], gets deflected, and travels 30.0 m [35° N of W]. Determine where the puck will end up with respect to its starting point, e.g., the puck's total displacement, using the three different methods discussed.

Answers

Hi, thank you for posting your question here at Brainly.

Basically, the problem asks you to find the resultant (R) vector quantity, which is the displacement. Illustrate the problem. Then, find the missing angles. In this case, the angle opposite to R is 150 degrees. Then, using the cosine law:

R^(2) = 30^(2) +20^(2) -2(30)(20)(cos150)
R = 48.36 m