The final velocity of the car can be found using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Plugging in the given values, we find that the car will be traveling at 24 m/s at 6 seconds.
To find the final velocity of a car accelerating at a constant rate, we can use the equation:
v = u + at
Where:
v is the final velocity, u is the initial velocity (which is zero in this case), a is the acceleration (4.0 m/s²), and t is the time (6 seconds).
Plugging in the values, we get:
v = 0 + (4.0 m/s²)(6s) = 24 m/s
Therefore, the car will be traveling at 24 m/s at 6 seconds.
#SPJ2
Answer:
1.1 x 10⁵m/s²
Explanation:
Given parameters:
Velocity = 452m/s
distance = 0.93m
Unknown:
Acceleration of the bullet = ?
Solution:
To solve this problem, we use one of the kinematics equation which is given below:
V² = U² + 2aS
V is the final velocity
U is the initial velocity = 0m/s
a is the unknown acceleration
S is the distance traveled
So;
452² = 0² + (2 x a x 0.93)
204304 = 1.86a
a = 1.1 x 10⁵m/s²
The acceleration of the bullet in the gun barrel can be calculated using the kinematic equation for motion. By substituying the given values into the equation, we find the acceleration to be approximately 1.095 x 10^5 m/s^2.
The subject of this question is Physics, specifically a topic under mechanics known as kinematics. The problem given can be solved using kinematic equations which are used to describe the motion of an object without considering the forces that cause it to move. In this case, the final velocity (vf) of the bullet is given as 452 m/s, the initial velocity (vi) is assumed to be 0 as it starts from rest, and the distance (d) is given as 0.93 m. We are asked to determine the value of acceleration (a).
Using the kinematic equation vf2 = vi2 + 2ad and substituting the given values, we get (452 m/s)2 = 0 + 2*a*0.93 m. We can rearrange to solve for acceleration to get: a = (452 m/s)2 / (2*0.93 m) = 109523.66 m/s2.
So, the acceleration of the bullet in the gun barrel is approximately 1.095 x 105 m/s2.
#SPJ3
Answer:
Plasma
Explanation:
Plasmais the most common because plasma is a gas that has been energized to the point that some of the electrons break
Answer:
water pushes against the squid
B. Interference is observed with light.
C. Diffraction is observed with light.
D. Unlike sound, light waves don't need a medium to self-propagate
The correct answer to the question is : D) Unlike sound, light waves don't need a medium to self-propagate
EXPLANATION:
Before coming into any conclusion, first we have to understand the nature of sound and light.
A sound wave is a longitudinal wave which requires a medium for its propagation. It can not move in space as space contains no material medium for its propagation.
Light is normally considered as electromagnetic wave which does not require any medium for its propagation. It can travel in space also.
The interference and diffraction can not be explained by the particle nature of light.
Hence, the argument that partially support that light behaves just like a particle is the last statement i.e Unlike sound, light waves do not need a medium to self-propagate.