What are some common factors of 25 and 250?

Answers

Answer 1
Answer: 1,5,25.
I do not think there are more.
Answer 2
Answer: in order to find common factors between 25 and 250, you need to list everything that has a product of their respective numbers like so:

1,5, 25
1,5,10,25,50,250

The common factors between 25 and 250 are 1, 5 and 25

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Help me solve this question plz

Answers

It is C
Graph them. It's easier
Happy to Help!
The answer is C because first of all it is diestance just count from -5 to two then 7 is ur answer

How did the light dress up for the costume party

Answers

its simple just when the lights turn off the light at the costume party in the electricity from the party turns on

Help me find the mean, median and mode to these problems?

Answers

sure but what numbers are there
I cant because there are no numbers

Jay evaluated the expression 3x(3+12 (divided by)3)-4 for his first step he added 3+12 to get 15. What is jays error? Find the correct answer. ( sorry their was no division sign)

Answers

Jay should have applied division operation first, then addition operation.

What is PEMDAS?

The abbreviation PEMDAS is used to indicate the sequence of steps to be taken when resolving expressions with multiple operations. P is for "parentheses," E is for "exponents," M is for "multiplication," D is for division, A is for addition, and S is for subtraction.

Given:

We have an expression,

3 × (3 + 12 ÷ 3) - 4.

In order to solve the problem,

we can use PEMDAS.

First, we solve parenthesis,

and division.

3 × (3 + 4) - 4.

Now,

3 × 7 - 4.

Now, multiplication,

21 - 4.

= 17

Therefore, the solution is 17.

To learn more about the PEMDAS;

brainly.com/question/36185

#SPJ2

By the order of operations, division takes place before addition.  So, (3+12/3) is not equal to (3+12)/3.  He should have gotten 3+12/3=3+4=7.

The number of dogs in a city is declining at a rate of about .08% eachyear. If there were 3500 cats to begin with, how many will there be in 10
years?

Answers

Answer:

There will be 3472 cats in 10 years

Step-by-step explanation:

There were 3500 cats

The number of dogs in a city is declining at a rate of about 0.08% each  year.

We are supposed to find the no. of cats in 10 years

Formula :N(t)=N_0(1-r)^t

Where N(t) = Remaining cats after t days

N_0 = Initial population

r = rate of depreciation

t=time

So, No. of cats remained after 10 years = 3500(1-(0.08)/(100))^(10)=3472.100

Hence There will be 3472 cats in 10 years

I need help on number one number two number three number four can you guys help me please I don't get it

Answers

for #2 you need to divide 100 by 17.