the answer is the car traveled 5km.
I know because i took the test a few weeks ago and got an A on it
sorry im late
oh and just remeber to put the answer i your own words and show show you got it.
hope this helps
2. An object with a height of 0.3 meter is placed at a distance of 0.4 meter from a concave
spherical mirror. An image with a height of 0.1 meter is formed in front of the mirror.
How far from the mirror is the image located?
3. When an object with a height of 0.10 meter is placed at a distance of 0.20 meter from a
convex spherical mirror, the image will appear to be 0.06 meter behind the mirror.
What's the height of the image?
4. Compare and contrast the properties of the images formed by each mirror type in the
table.
Answer:
1. 12 cm
2. 0.133 m
3. 0.03 m
4. Plane mirror
Virtual image
Upright
Behind the mirror
The same size as the object
Concave mirror when the object is located a distance greater than the focal length from the mirror's surface
Real image
Inverted image
In front of the the mirror
Diminished when the object is beyond the center of curvature
Same size as object when the object is placed at the center of curvature
Enlarged when the object is placed between the center of curvature of the mirror and the focus of the mirror
Concave mirror when the object is located a distance less than the focal length from the mirror's surface
Virtual image
Upright image
Behind the the mirror
Enlarged
Convex mirror
Type = Virtual image
Appearance = Upright image
Placement = Behind the mirror
Size = Smaller than the object
Explanation:
1. For plane mirror, since there is no magnification, the virtual image distance from the mirror = object distance from the mirror = 12 cm behind the mirror
2. The height of the object = 0.3 m
The distance of the object from the mirror = 0.4 meters
Height of image formed = 0.1 meter
We have;
Image distance from the mirror = 0.1/0.3×0.4 = 2/15 = 0.133 m
Image distance from the mirror = 0.133 m
3.
The image height = 0.06/0.2×0.1 = 3/100 = 0.03 meter
The image height = 0.03 meter
4. Plane mirror
Type = Virtual image
Appearance = Upright image with the left transformed to right
Placement = Behind the mirror
Size = The same size as the object
Concave mirror when the object is located a distance greater than the focal length from the mirror's surface
Type = Real image
Appearance = Inverted image
Placement = In front of the the mirror
Size = Diminished when the object is beyond the center of curvature
Same size as object when the object is placed at the center of curvature
Enlarged when the object is placed between the center of curvature of the mirror and the focus of the mirror
Concave mirror when the object is located a distance less than the focal length from the mirror's surface
Type = Virtual image
Appearance = Upright image
Placement = Behind the the mirror
Size = Enlarged
Convex mirror
Type = Virtual image
Appearance = Upright image
Placement = Behind the mirror
Size = Smaller than the object.
Answer:
1. The mirror is 12 centimeters away from the image. This is a plane mirror with a flat reflecting surface. The distance between the object and the mirror surface is equal to the distance between the mirror surface and the image.
2. hiho=siso
0.1 m0.3 m=si0.4 m
Multiply each side of this equation by 0.4.
0.4×(0.10.3=si0.4)×0.4
si=0.40.3
si = 0.133 m
3. hiho=siso
hi0.10 m=0.06 m0.02 m
Multiply each side of this equation by 0.10.
0.10×(hi0.10=0.060.20)×0.10
hi=0.0060.20
hi = 0.03 m
4.
Image Formation
Mirror Type Appearance Placement Size
Plane Virtual Erect (Upright); Appears to have left and right reversed Behind the mirror; the distance between the mirror and the image is equal to the distance between the mirror and the object Depends on the size of the mirror and placement of the object
Concave (when the object is located a distance greater than a focal length from mirror's surface) Real Inverted In front of the mirror Smaller than the object
Concave (when object is located a distance less than the focal length of the mirror) Virtual Erect (Upright) Behind the mirror Enlarged
Convex Virtual Erect (Upright) Behind the mirror Smaller than the object
Explanation:
PENN
Answer:
196 J
Explanation:
PE = mgh
PE = (10 kg) (9.8 m/s²) (2 m)
PE = 196 J
As per the modern classificationsystem, the class, order, genus, species is arranged from least specific to most specific one. The correct option is C.
The term classification can refer to one or more of the following: the process of classifying the resulting set of classes the classification of elements into predefined classes Classifying, in its broadestsense, is a fundamental concept and a component of almost all activities.
In 1956, Herbert FaulknerCopeland (1902-1968) proposed the four kingdom classification.
Monera, Protista, Plantae, and Animalia were the four kingdoms. He classified unicellular organisms into two groups: the Monera kingdom and the Protista kingdom.
The classificationsystem provides a wealth of information about organism characteristics. Using scientific names as a shorthand method of describing a plant or animal can thus be beneficial.
Thus, the correct option is C.
For more details regarding biological classification, visit:
#SPJ2
Your question seems incomplete, the missing options are:
A) species, genus, family, order
B) phylum, class, genus, order
C) class, order, genus, species
D) phylum, order, species, family
Answer:
The patent limits the sharing of important scientific knowledge.
Explanation: