What is 6.64 rounded to the nearest tenth

Distance between the points (4, 7) and (4, –5) is 12 units and distance between the points (–3, 5) and (2, –6) is 12.01 units.

What is Distance?

The length along a line or line segment between two points on the line or line segment.

Distance=√(x₂-x₁)²+(y₂-y₁)²

The distance between the points (4, 7) and (4, –5)

x₁=4, y₁=7, x₂=4, y₂=-5

Distance=√(x₂-x₁)²+(y₂-y₁)²

Distance=√(4-4)²+(-5-7)²

=√(-12)²

=√144

=12

Hence  distance between the points (4, 7) and (4, –5) is 12 units.

the distance between the points (–3, 5) and (2, –6)

x₁=-3, y₁=5, x₂=2, y₂=-6

Distance=√(x₂-x₁)²+(y₂-y₁)²

=√(2-(-3))²+(-6-5)²

=√(5)²+(-11)²

=√25+121

=√146

=12.08

So distance between the points (–3, 5) and (2, –6) is 12.01 units.

Hence  distance between the points (4, 7) and (4, –5) is 12 units and distance between the points (–3, 5) and (2, –6) is 12.01 units.

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Answer:

a) 29.50 miles per gallon    b) 29.87 miles per gallon     c) 28.19 miles per gallon

Step-by-step explanation:

A specific car fuel economy (miles/gallon) = f(x) = 0.00000056x^4 - 0.000018x^3 - 0.016x^2 + 1.38x - 0.38

where x represents the car speed in miles per hour.

when x = 40 miles per hour

A specific car fuel economy (miles/gallon) = f(x) = 0.00000056(40)^4 - 0.000018(40)^3 - 0.016(40)^2 + 1.38(40) - 0.38 = 1.4336 - 1.152 - 25.6 + 55.2 - 0.38 = 29.50 miles per gallon

Similarly,

when x = 50

A specific car fuel economy (miles/gallon) = f(x) = 0.00000056(50)^4 - 0.000018(50)^3 - 0.016(50)^2 + 1.38(50) - 0.38 = 3.5 - 2.25 - 40 + 69 - 0.38 = 29.87 miles per gallon

Similarly,

when x = 60

A specific car fuel economy (miles/gallon) = f(x) = 0.00000056(60)^4 - 0.000018(60)^3 - 0.016(60)^2 + 1.38(60) - 0.38 = 7.26 - 3.89 - 57.6 + 82.8 - 0.38 = 28.19 miles per gallon