In golf, scores are often written in a relationship to par, the average score for a round at a certain course. Write an integer to represent a score that is 7 under par.

Answers

Answer 1
Answer: Because the situation represents under par, the integer is –7. So its -7
Answer 2
Answer: I think the correct answer is -7 hope this helps

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The Martins drove the 468 miles between Memphis, Tennessee and Cincinnati, Ohio in one day. If they left Memphis at 7 a.m. and arrived in Cincinnati at 4 p.m., what was the Martins’ average speed?

Answers

52mph, depending what unit you need the answer in you may have to use conversions

A central angle of a circle measures 1.2 radians, and the length of the related intercepted arc measures 6 cm. What is the diameter of the circle?

Answers

Answer:

The diameter of the circle is 10 cm.

Step-by-step explanation:

As

  • A central angle of a circle measures 1.2 radians, and
  • The length of the related intercepted arc measures 6 cm.

The arc length formula is given by:

s\:=\:r\theta

where

  • r is the radius of the circle
  • \theta is the central angle in radians

First lets find r,

\:(s)/(\theta \:)\:=\:r

(6)/(1.2\:)\:=\:r         ∵ s = 6 cm and \theta = 1.2 radians

\:r\:=\:5\:cm

As

  • Diameter 'd' is 2r.

so

d\:=\:2r

d\:=\:2\left(5\right)

d = 10 cm

Therefore, the diameter of the circle is 10 cm.

Answer:

Its 10 cm

Step-by-step explanation:

By how much is 5/8 greater than 1/4 of 1/2

Answers

the answer is five percent
1/4 of 1/2 is 1/8 so 5/8 is 1/2 greater then 1/4 of 1/2.
Hope this helps.

The vertices of a parallelogram are shown below. (0, 0), (27, 0), (36, 30), (9, 30)

Which of the following points is a vertex for the image produced by a dilation about the origin with a scale factor of 1/3?









A.

(3, 3)

B.

(10, 9)

C.

(3, 15)

D.

(3, 10)

Answers

The vertices for the dilated image can be found by multiplying the coordinates of the original image by the scale factor. In this problem, the scale factor is 1/3.

(0,0) ⇒ 0 x 1/3 = 0 ; 0 x 1/3 = 0 ⇒ (0,0)
(27,0) ⇒ 27 x 1/3 = 9 ; 0 x 1/3 = 0  ⇒ (9,0)
(36,30) ⇒36 x 1/3 = 12 ; 30 x 1/3 = 10 ⇒ (12,10)
(9,30) ⇒ 9 x 1/3 = 3 ; 30 x 1/3 = 10 ⇒ (3,10)

Answer is choice D. (3,10)

Factor completely 3x2 - 21.

Answers

3x² - 21

Factor 3 from both terms:

3 (x² - 7)

To me, that's as far as you should need to go.  But if you want to get
completely carried away, you could go one step further, since you have
the difference of two squares:

3 (x + √7) (x - √7)

Of course, there's no end now, because the last binomial could be
considered another difference of two squares, so you'd have to
factor that too:

3 (x + √7) (√x + ⁴√7) (√x - ⁴√7)

but to me, this would be nonsense.
3x^2-21=3(x^2-7)=3[x^2-(\sqrt7)^2]=3(x-\sqrt7)(x+\sqrt7)

Please help!Which point is collinear with points B and C?



A.
(0, 0)

B.
(1, 1)

C.
(1, –5)

D.
(6, –8)

Answers

Answer:  Option 'A' is correct.

Step-by-step explanation:

Since we have given that

Coordinates of B = (4,-3)

Coordinates of C = (-4,3)

We need to find the collinear  point with B and C.

There is one method to find the collinear point i.e. Slope method.

Slope of BX = Slope of CX =  (y_2-y_1)/(x_2-x_1)

Let Coordinates of X = (0,0)

So, Slope of BX is given by

(0+3)/(0-4)=(3)/(-4)

Slope of CX is given by

(0-3)/(0+4)=(-3)/(4)

So, Slope of BX = Slope of CX = (-3)/(4)

And we can see from the graph (0,0) is the collinear point with B and C too.

Hence, Option 'A' is correct.

Points are collinear if they lie on the same line.

First find the equation of the line that passes through the points B and C.
B(4, -3) \nx_1=4 \n y_1=-3 \n \nC(-4,3) \nx_2=-4 \n y_2=3 \n \nm=(y_2-y_1)/(x_2-x_1)=(3-(-3))/(-4-4)=(3+3)/(-8)=(6)/(-8)=-(3)/(4) \n \ny=-(3)/(4)x+b \n(-4,3) \n3=-(3)/(4) * (-4)+b \n3=3+b \nb=0 \n \ny=-(3)/(4)x

The points lie on the line y=(-3/4)x.
Now plug the coordinates of the given points into the equation and check if they satisfy the equation.

(0,0) \nx=0 \n y=0 \n \Downarrow \n0 \stackrel{?}{=} -(3)/(4) * 0 \n0 \stackrel{?}{=} 0 \n0=0 \n\hbox{the point lies on the line} \n \n(1,1) \nx=1 \n y=1 \n \Downarrow \n1 \stackrel{?}{=} -(3)/(4) * 1 \n1 \stackrel{?}{=} -(3)/(4) \n1 \not= -(3)/(4) \n\hbox{the point doesn't lie on the line}

(1,-5) \nx=1 \n y=-5 \n \Downarrow \n -5 \stackrel{?}{=} -(3)/(4) * 1 \n-5 \stackrel{?}{=} -(3)/(4) \n-5 \not= -(3)/(4) \n\hbox{the point doesn't lie on the line} \n \n(6,-8) \nx=6 \n y=-8 \n \Downarrow \n-8 \stackrel{?}{=} -(3)/(4) * 6 \n-8 \stackrel{?}{=} -(9)/(2) \n-8 \not= -(9)/(2) \n\hbox{the point doesn't lie on the line}

The answer is A.